Question

Factor by grouping. 9c^3-12c^2+18c-24

Answer 1

Answer:

$9c^3 - 12c^2 - 18c - 24= [3c^2 - 6][3c - 4]$

Step-by-step explanation:

Given

$9c^3 - 12c^2 - 18c - 24$

Required

Factor

Group into 2

$[9c^3 - 12c^2] - [18c + 24]$

Factorize each group

$3c^2[3c - 4] - 6[3c - 4]$

Factor out 3c - 4

$[3c^2 - 6][3c - 4]$

Hence:

$9c^3 - 12c^2 - 18c - 24= [3c^2 - 6][3c - 4]$