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ololo11 [35]
3 years ago
8

HELP PLEASE!!!!!!

Mathematics
2 answers:
Westkost [7]3 years ago
8 0
False true true false true false
spayn [35]3 years ago
5 0

Answer:

The function is discontinuous at x = 1.

The value of the function is never negative.

The value of the function at x = -1 is 0

Step-by-step explanation:

Given is a graph of   a function first a straight line, followed by a semi circle centred at the origin and another piece of straight line not connected to the other graph.

We can see that the funciton is discontinuous at x=1 since

right limit = 1 and left limit =0

x=1 is in the domain .

f(-1) =0 is right

But f(1) =0 is incorrect

Thus correct options are

The function is discontinuous at x = 1.

The value of the function is never negative.

The value of the function at x = -1 is 0

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√272 is a real number, and the simplified expression of √272 is 4√17

<h3>How to simplify the expression?</h3>

The expression is given as:

√272

Expand

√272 = √16 * 17

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