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3 years ago

HELP PLEASE!!!!!!

Mathematics

2 answers:

Westkost [7]3 years ago

8 0

False true true false true false

spayn [35]3 years ago

5 0

Answer:

The function is discontinuous at x = 1.

The value of the function is never negative.

The value of the function at x = -1 is 0

Step-by-step explanation:

Given is a graph of a function first a straight line, followed by a semi circle centred at the origin and another piece of straight line not connected to the other graph.

We can see that the funciton is discontinuous at x=1 since

right limit = 1 and left limit =0

x=1 is in the domain .

f(-1) =0 is right

But f(1) =0 is incorrect

Thus correct options are

The function is discontinuous at x = 1.

The value of the function is never negative.

The value of the function at x = -1 is 0

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Allisa [31]

Answer:

Question A)

$=\sqrt{6}x$

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Question C)

$=5\sqrt{2}b^2$

Step-by-step explanation:

We are given:

$\sqrt{6x^2}\, \text{ where } x\geq 0$

We can rewrite the expression:

$=\sqrt{6}\cdot \sqrt{x^2}$

The square root and square will cancel each other out. Thus:

$=\sqrt{6}x$

We are given:

$\sqrt{9a^3}$

Rewrite:

$=\sqrt{9}\cdot \sqrt{a^3}$

Note that the square root of 9 is simply 3. We can also factor the second part:

$=3\cdot \sqrt{a^2\cdot a}$

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$=3\cdot\sqrt{a^2}\cdot\sqrt{a}$

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$=3a\sqrt{a}$

We are given:

$\sqrt{50b^4}$

Rewrite. Note that 50 = 25(2):

$=\sqrt{25}\cdot \sqrt{2}\cdot \sqrt{b^4}$

Simplify. We can rewrite the factor as:

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$=5\sqrt{2}b^2$

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3 years ago

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Yanka [14]

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3 years ago

Can someone help me with this

jarptica [38.1K]

The answer is:

x=-8

Because:

If you pick a number(-8) to fill in the equation written below

5x+20+5x=5x-20

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3 years ago

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icang [17]

Answer:

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Step-by-step explanation:

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2 years ago

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Which equation can be used to solve for b? B 5 cm 10 cm 30°

kati45 [8]

The Question is Incomplete The complete question with figure is below.

Answer:

Therefore the equation to solve for b is

$\tan 30 = \dfrac{5}{b}$

Step-by-step explanation:

Given:

In Right Angle Triangle ABC

∠C = 90°

BC = 5 cm

AB = 10 cm

∠A = 30°

To Find:

b = ?

Solution:

In Right Angle Triangle ABC Tangent identity we have

$\tan A = \dfrac{\textrm{side opposite to angle A}}{\textrm{side adjacent to angle A}}$

Substituting the values we get

$\tan 30 = \dfrac{BC}{AC}\\\\\tan 30 = \dfrac{5}{b}$

Therefore the equation to solve for b is

$\tan 30 = \dfrac{5}{b}$

6 0

3 years ago