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Marina CMI [18]
3 years ago
12

Solve for the roots in simplest form using the quadratic formula: 4x^2 -28x= -53

Mathematics
1 answer:
irinina [24]3 years ago
3 0

Answer:

x = (28 +- root -64) / (8)

Step-by-step explanation:

4x^2 -28x= -53 = 0

x = [-(-28)+- root (-28)^2 - 4 * 4 * 53] / 2 *4

x = (28 +- root 784 - 848) / (8)

x = (28 +- root -64) / (8)

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Suppose that X is a random variable with mean 30 and standard deviation 4. Also suppose that Y is a random variable with mean 50
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Answer:

a) Var[z] = 1600

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Step-by-step explanation:

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how in this problem Cov[XY] = 0, then

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Also we must use this properti of the variance  

V[ax+b] = a^{2}V[x]

and remember that

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a) z = 35-10x

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b) z = 12x -5

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   D[z] = \sqrt{80} = 8.94

e) z = -2x + 2y

   Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320

  D[z] = \sqrt{320} = 17.88

   

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