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Illusion [34]
3 years ago
6

How many feet are in 4725 miles

Mathematics
1 answer:
n200080 [17]3 years ago
3 0
4725mi= 24948000ft
There are 5280 feet in every mile!
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The length of one base of a trapezoid is 19 less than five times the length of the other base. If the trapezoid has a height of
love history [14]
Area of a trapezoid: [(top +bottom)*height]/2
suppose the length of one base is x, then the other base is 5x-19
[(x+5x-19)*18]/2=477
[6x-19]*18=954
6x-19=53
6x=72
x=12
The longer base is 5*12-19=41


5 0
3 years ago
1/2(4x-2)-2/3(6x+9) greater or equal to 4
Simora [160]
1/2(4x-2)-2/3(6x+9)
(2x-1)-(4x+6)
2x-1-4x+62x-4x-1+6
-2x+5=2.5
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8 0
3 years ago
Which expression is equivalent to (3x² + 4x - 7)(x - 2)? (Apex)
katovenus [111]

Answer:

A i think

Step-by-step explanation:

3 0
3 years ago
Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

6 0
1 year ago
Pls help easy points
damaskus [11]
Are you just looking for the green space or more
7 0
3 years ago
Read 2 more answers
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