Answer:
-23x^3+20x^4+25x^2+84x-84
Step-by-step explanation:
1 Expand by distributing sum groups.
4x^2(3x+5x^2-6)-7x(3x+5x^2-6)+14(3x+5x^2-6)
2 Expand by distributing terms.
12x^3+20x^4-24x^2-7x(3x+5x^2-6)+14(3x+5x^2-6)
3 Expand by distributing terms.
12x^3+20x^4-24x^2-(21x^2+35x^3-42x)+14(3x+5x^2-6)
4 Expand by distributing terms.
12x^3+20x^4-24x^2-(21x^2+35x^3-42x)+42x+70x^2-84
5 Remove parentheses.
12x^3+20x^4-24x^2-21x^2-35x^3+42x+42x+70x^2-84
6 Collect like terms.
(12x^3-35x^3)+20x^4+(-24x^2-21x^2+70x^2)+(42x+42x)-84
7 Simplify.
-23x^3+20x^4+25x^2+84x-84
Y= 1/4x+b
-3= 1/4(-4) +b
-3= -1 +b
-2 = b
y=1/4x-2
Answer: 16.6% percent chance she will pull out a blue or orange marker.
Hope this helps! :)
Answer:
If the person bout one box of chocolate O's than they paid $2.2 for 12 ounces
X - tickets
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167x + 19x + 16 = 1132
186x + 16 = 1132
186x = 1132 - 16
186x = 1116
x = 1116 : 186
x = 6 tickets (answer).