Answer:
1/25 ; 3/20 ; 3/50
Step-by-step explanation:
Total number of stickers :
(10 + 15 + 25) = 50 stickers
Probability = required outcome / Total possible outcomes
a. Selecting blue and blue stickers
P(First blue) = 10/50 = 1/5
P(second blue) = 10/50 = 1/5
1/5 * 1/5 = 1 / 25
b. Selecting one red sticker and then one orange sticker
P(First red) = 15/50 = 3/10
P(second orange) = 25/50 = 1/2
3/10 * 1/2 = 3 /20
Selecting one red sticker and then one blue sticker
P(First red) = 15/50 = 3/10
P(second blue) = 10/50 = 1/5
3/10 * 1/5 = 3 / 50
C because I did the math on an app so it’s right
Question:
A drink dispenser in a fast-food restaurant holds 250 litres of lemonade. How many 0.6-litre drinks can be dispensed before a refill is needed?
Answer:
The number 0.6-litre drinks can be dispensed before a refill is needed is 416
Step-by-step explanation:
Given:
The capacity of the drink dispenser = 250 litres
To Find:
Number of 0.6-litre drinks can be dispensed before a refill is needed = ?
Solution
Let the number of 0.6-litre drinks can be dispensed before a refill is needed be x
Then

On substituting the values we get
x = 416. 667
Thus only 416 can be filled