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3 years ago

14

Classify the shape as precisely as possible based on its marking

1 answer:

Anna [14]3 years ago

6 0

Answer:

rhombus

Step-by-step explanation:

in square and rectangle there are 90 degrees

and in parallelogram only opposite sides eq.

but in rhombus all sides are eq. and angle can be any

hence ans is rhombus

PLZ MARK IT BRAINLIEST

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Solve the following <br> 8903=e

Semenov [28]

$\huge\text{Hey there!}$

$\huge\textbf{Equation:}$

$\mathsf{8,903 = e^{5x}}}$

$\huge\textbf{Simplify:}$

$\mathsf{8,903 = e^{5x}}}$

$\mathsf{e^{5x} = 8,903}}$

$\huge\textbf{Solve for the exponent:}$

$\large\textsf{We get: }\downarrow\\\\\mathsf{2.718282^{5x}=8903}$

$\huge\textbf{Take the logarithm from both sides:}$

$\mathsf{log(2.718282^{5x}) = log(8,903x)}$

$\large\textsf{We get:}\\\\\mathsf{5x \times log(2.718282)=log(8903)}$

$\huge\textbf{Simplify it:}$

$\mathsf{5x = \dfrac{log(8903)}{log(2.718282)}}$

$\large\textsf{We get: }\\\\\mathsf{5x = 9.094143}$

$\huge\textbf{Divide 5 to both sides:}$

$\mathsf{\dfrac{5x}{5} = \dfrac{9.094143}{5}}$

$\huge\textbf{Simplify it:}$

$\mathsf{x= \dfrac{9.094143}{5}}$

$\mathsf{x = 1.818829}$

$\mathsf{x \approx 2}$

$\huge\textbf{Therefore, your answer should be:}$

$\huge\boxed{\mathsf{x =}\frak{\ 1.818829}}\huge\checkmark$

$\large\textbf{Or if you're estimating your answer}\downarrow$

$\huge\boxed{\mathsf{x \approx }\frak{\ 2}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

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