Answer:
a) t =12[s]; b) x = 348[m]
Explanation:
We can solve this problem using the following kinematics equations:
a)
where:
vf = final velocity = 12 [m/s]
vo= initial velocity = 6 [m/s]
a = acceleration = 0.5[m/s^2]
t = time [s]
Now clearing the time t, we have:
b)
We can calculate the displacement for the first 12 [s] then using the equation for the constant velocity we can calculate the other displacement for the 20[s].
The we can calculate the second displacement for the constant velocity:
x = x1 + x2
x = 108 + 240
x = 348[m]
Answer:
I am just 13 and thanks for point
Answer: D just took the test
Explanation:
The net force (magnitude and direction) of the system given in the question is 40 N horizontal to the right
<h3>How to determine the net force</h3>
Case 1 (Net force between up and downward force)
- Force up (Fu) = 50 N
- Force down (Fd) = 30 N
- Net force 1 (F1) = ?
F1 = Fu - Fd
F1 = 50 - 30
F1 = 20 N up
Case 2 (Net force between right and left)
- Force right (Fr) = 60 N
- Force left (Fl) = 20 N
- Net force 2 (F2) = ?
F2 = Fr - Fl
F2 = 60 - 20
F2 = 40 N right
SUMMARY
- Net force between up and down = 20 N up
- Net force between right and left = 40 N right
From the above, the net force between right and left (i.e 40 N) is greater than the net force between up and down (i.e 20 N)
Thus, the net force of the system will be 40 N horizontal to the right
Learn more about force:
brainly.com/question/14361879
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