A lead pellet of mass 10.0g is shot horizontally into a stationary wooden block of mass 100g. The pellet hits the block with an
impact velocity of 250ms^–1. It embeds itself in the block and it does not emerge.
What will be the speed of the block immediately after the pellet is embedded?
What will be the speed of the block immediately after the pellet is embedded?
1 answer:
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Answer:
5.4 J.
Explanation:
Given,
mass of the object, m = 2 Kg
initial speed, u = 5 m/s
mass of another object,m' = 3 kg
initial speed of another orbit,u' = 2 m/s
KE lost after collusion = ?
Final velocity of the system
Using conservation of momentum
m u + m'u' = (m + m') V
2 x 5 + 3 x 2 = ( 2 + 3 )V
16 = 5 V
V = 3.2 m/s
Initial KE =
=
= 31 J
Final KE =
Loss in KE = 31 J - 25.6 J = 5.4 J.