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Sedbober [7]
3 years ago
13

A lead pellet of mass 10.0g is shot horizontally into a stationary wooden block of mass 100g. The pellet hits the block with an

impact velocity of 250ms^–1. It embeds itself in the block and it does not emerge.
What will be the speed of the block immediately after the pellet is embedded?

Physics
1 answer:
Roman55 [17]3 years ago
6 0
Hope this helps you.

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A car travels from point A to point B, moving in the same direction but with a non-constant speed. The first half of the distanc
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Answer:

Explanation:

From A to B

distance traveled with velocity v_1  in time t_1

\frac{d}{2}=v_1t_1----1

from B to C

distance traveled is 0.5 d with v_2  and v_3  velocity for half-half time

\frac{d}{2}=\frac{v_2t_2}{2}+\frac{v_3t_3}{2}----2

divide 1 and 2 we get

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v_{avg}=\frac{d}{t_1+t_2}

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v_{avg}=\frac{2v_1t_1}{t_1(1+\frac{t_2}{t_1})}

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v_{avg}=\frac{2v_1(v_2+v_3)}{2v_1+v_2+v_3}  

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