A lead pellet of mass 10.0g is shot horizontally into a stationary wooden block of mass 100g. The pellet hits the block with an
impact velocity of 250ms^–1. It embeds itself in the block and it does not emerge.
What will be the speed of the block immediately after the pellet is embedded?
What will be the speed of the block immediately after the pellet is embedded?
1 answer:
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Actually what the problem meant about the westward component of the ball’s displacement is the horizontal component of the displacement. To help us better understand the problem, I attached a figure of the situation.
We can see from the figure that to solve for the value of the horizontal component, we have to make use of the sin function. That is:
sin θ = side opposite to the angle / hypotenuse of the triangle
sin 42 = x / 40 m
x = (40 m) sin 42
x = 26.77 m
Therefore the ball has a westward displacement of about 26.77 m
