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QveST [7]
3 years ago
11

1 A ball is rolling along the floor with a constant velocity of 8 m/s. How far will it have gone after

Physics
1 answer:
Dennis_Churaev [7]3 years ago
3 0

Answer:

448 meters

Explanation:

every second it moves 8 meters, so all you have to do is multiply 56x8 or 8x56 either way it is the same thing and you will get the same answer

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A woman lifts her 150 N child up one meter and carries her for a distance of 50 meters to the
Cloud [144]

7500J

Explanation:

Given parameters:

Weight of child = 150N

Height of lifting = 50m

Distance = 50m

Unknown:

Work done by the woman = ?

Solution:

Work done by a body is the force applied to move a body through a given distance.

  Work done = Force x distance

Weight is a force impacted by the mass of a body and the gravity on it.

 input the parameters:

   Work done = 150 x 50 = 7500J

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

3 0
3 years ago
In a loop-the-loop ride a car goes around a vertical, circular loop at a constant speed. The car has a mass m = 268 kg and moves
11111nata11111 [884]
Before we go through the questions, we need to calculate and determine some values first.

r = 11.5 m 
<span>m = 280 kg </span>
<span>Centripetal force = m x v^2/r = 280 x (17.1^2/11.5) = 7119.55 N 
</span>
1) What is the magnitude of the normal force on the care when it is at the bottom of the circle. 

<span>Centripetal force + mg = 7119.55 + (280 x 9.8) = 9863.55 N </span>

<span>2) What is the magnitude of the normal force on the car when it is at the side of the circle. </span>

<span>Centripetal force = 7119.55 N </span>


<span>3) What is the magnitude of the normal force on the car when it is at the top of the circle. </span>

<span>Centripetal force - mg = 7119.55 - (280 x 9.8) = 4375.55 N </span>

<span>4) What is the minimum speed of the car so that it stays in contact with the track at the top of the loop. </span>

√<span>(gr) </span>

√<span>(9.8 x 11.5) = 10.62 m/s</span>
7 0
3 years ago
If the value of the electric field in an electromagnetic wave were doubled then
Norma-Jean [14]

Answer:

Electromagnetic wave are waves formed as a result of the oscillatory activities involving the electric and the magnetic field.

However in an Electromagnetic wave, the electric field and magnetic field carry equal amounts of energy and the magnitude of the electric field is directly proportional to the magnitude of the magnetic field. This direct proportionality gives rise to the speed of light being the constant between the two fields.

When the electric field is doubled then an equal action is to be set for the magnetic field so it doesn’t deviate from its main functions and characteristics.

4 0
3 years ago
What is evaporation? Condensation? Drag the terms on the left to the appropriate blanks on the right to complete the sentences.
krok68 [10]

Answer:

Evaporation is the physical change in which a substance converts from its <u>liquid</u> state to its <u>gaseous</u> state. Condensation is the physical change in which a substance converts from its <u>gaseous</u> state to its <u>liquid</u> state.

Explanation:

Evaporation and condensation are opposite processes to each other. Evaporation changes a liquid to a gas and condensation is the reverse.

7 0
4 years ago
A circular coil of wire having a diameter of 20.0 cm and 3000 turns is placed in the earth's magnetic field with the normal of t
Bess [88]

Explanation :

It is given that,

Diameter of the coil, d = 20 cm = 0.2 m

Radius of the coil, r = 0.1 m

Number of turns, N = 3000

Induced EMF, \epsilon=1.5\ V

Magnitude of Earth's field, B=10^{-4}\ T

We need to find the angular frequency with which it is rotated. The induced emf due to rotation is given by :

\epsilon=NBA\omega

\omega=\dfrac{\epsilon}{NBA}

\omega=\dfrac{1.5}{3000\times 10^{-4}\times \pi (0.1)^2}

\omega=159.15\ rad/s

So, the angular frequency with which the loop is rotated is 159.15 rad/s. Hence, this is the required solution.

3 0
3 years ago
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