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QveST [7]
2 years ago
11

1 A ball is rolling along the floor with a constant velocity of 8 m/s. How far will it have gone after

Physics
1 answer:
Dennis_Churaev [7]2 years ago
3 0

Answer:

448 meters

Explanation:

every second it moves 8 meters, so all you have to do is multiply 56x8 or 8x56 either way it is the same thing and you will get the same answer

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3 years ago
A projectile is fired at 0=433.0 m/s
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Answer:

10,600 m

Explanation:

Use range equation:

R = v₀² sin(2θ) / g

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3 years ago
The speed of sound in steel is 5000 m/s. What is the wavelength of a sound wave of frequency 660 Hz in steel?
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5 0
3 years ago
A 200 kg boulder is 1000m above the ground. What is the speed of the object right before it hits the ground?
dem82 [27]

Answer:

140.07m/s

Explanation:

we use the equation for the final speed:

v_{f}^2=v_{0}^2+2gh

where v_{f} is the final speed, v_{0} is the initial speed, g is the gravitational acceleration (g=9.81m/s^2) and h is the height.

In this case we don't have an initial velocity indicated so: v_{0}=0, and we are told that the boulder is at a height: h=1,000m.

We substitute this values into the equation:

v_{f}^2=2gh\\v_{f}^2=2(9.81m/s^2)(1,000m)\\v_{f} ^2=19,620m^2/s^2\\\\v_{f}=\sqrt{19,620m^2/s^2} \\v_{f}=140.07m/s

the speed of the object right before it hits the ground is 140.07m/s

6 0
3 years ago
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