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Tcecarenko [31]
3 years ago
6

Scientists must evaluate their work in order to?

Physics
1 answer:
AnnZ [28]3 years ago
6 0
B. Ensure that their results are accurate and reliable
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What do these weapon stats mean?
kaheart [24]

Answer:

its sort of like how Pounds are measured in lbs

Explanation:

Pounds are measured in lbs when they dont sound anything similar, same thing applies to gun technology.

5 0
3 years ago
Three cars with identical engines and tires start from rest, and accelerate at their maximum rate. Car X is the most massive, an
aksik [14]

Answer:C) car X

Explanation:

Given

All the cars have identical Engine thus Force Produced by car X will be equal to  Y and Z

and Force=mass\times acceleration

Since Car X is most massive so acceleration associated with it will be minimum

acceleration of car X is minimum thus it will travel farthest  

6 0
3 years ago
A 600g boulder has a density of 8 g/cm3. What is the volume of the boulder
Amiraneli [1.4K]
Density can be calculated using the following rule:
density = mass / volume

Since the density is given as 8 gm/cm^3 and the mass is given as 600 grams, therefore, all we need to do is substitute in the equation to get the value of the volume as follows:
8 = 600 / volume
volume = 600 / 8 = 75 cm^3
3 0
4 years ago
The dots on an hr diagram represent which of the following?
gladu [14]
The dots on an hr diagram represent stars.
5 0
3 years ago
A family uses an electric frying pan with a power rating of 1.2 X 10^3 W. Although the pan is thermostatically controlled, its e
kirill115 [55]

Answer:

378 KWh

Explanation:

We'll begin by converting 1.2×10³ W to KW. This can be obtained as follow:

10³ W = 1 KW

Therefore,

1.2×10³ W = 1.2×10³ W × 1 KW / 10³ W

1.2×10³ W = 1.2 KW

Next, we shall convert 6.3×10² mins to hours (h). This can be obtained as follow:

60 mins = 1 h

Therefore,

6.3×10² mins = 6.3×10² mins × 1 h / 60 mins

6.3×10² mins = 10.5 h

Finally, we shall determine the electrical energy in KWh used for 1 month (i.e 30 days). This can be obtained as follow:

Power (P) = 1.2 KW

Time (t) for 1 month (30 days) = 10.5 h × 30

= 315 h

Energy (E) =?

E = Pt

E = 1.2 × 315

E = 378 KWh

Thus, the electrical energy used for 1 month (i.e 30 days) is 378 KWh.

8 0
3 years ago
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