Answer:
but its right
Step-by-step explanation:
The area of a rectangle is A=LW, the area of a square is A=S^2.
W=S-2 and L=2S-3
And we are told that the areas of each figure are the same.
S^2=LW, using L and W found above we have:
S^2=(2S-3)(S-2) perform indicated multiplication on right side
S^2=2S^2-4S-3S+6 combine like terms on right side
S^2=2S^2-7S+6 subtract S^2 from both sides
S^2-7S+6=0 factor:
S^2-S-6S+6=0
S(S-1)-6(S-1)=0
(S-6)(S-1)=0, since W=S-2, and W>0, S>2 so:
S=6 is the only valid value for S. Now we can find the dimensions of the rectangle...
W=S-2 and L=2S-3 given that S=6 in
W=4 in and L=9 in
So the width of the rectangle is 4 inches and the length of the rectangle is 9 inches.
Here you go, and please mark brainliest :)
Answer:
Infinitely Many Solutions
Step-by-step explanation:
Given
![\left[\begin{array}{cccccc}1&2&3&4&5&6\\7&6&5&4&3&2\\8&8&8&8&8&8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccccc%7D1%262%263%264%265%266%5C%5C7%266%265%264%263%262%5C%5C8%268%268%268%268%268%5Cend%7Barray%7D%5Cright%5D)
Required
Determine the type of solution
From the matrix, we have:
3 non-zero rows and 5 variables (the last column is the result)
When the number of variables is more than the number of non-zero rows, then such system has infinitely many solutions
i.e.
