Question

Write an application that stores the following nine integers in an array: 10, 15, 19, 23, 26, 29, 31, 34, 38. Display the integers from first to last, and then display the integers from last to first.

Answer 1

Answer:

Following are the code to this question:

#include <iostream>// header file

using namespace std;

int main()//main method

{

int arr1[]= {10, 15, 19, 23, 26, 29, 31, 34, 38};//defining array of integer values

int i;//defining integer variable

cout<<" Array from first to last: ";//print message

for(i=0;i<9;i++)//use for loop to print array

{

cout<<arr1[i]<<" ";//print array value

}

cout<<"\n Array from last to first : ";//print message

for(i=9-1;i>=0;i--)//defining for loop to print array in reverse order

{

cout<<arr1[i]<<" ";//print array

}

return 0;

}

Output:

Array from first to last: 10 15 19 23 26 29 31 34 38  

Array from last to first : 38 34 31 29 26 23 19 15 10  

Explanation:

In the above-given code, an array "arr1" of an integer value is declared, that stores 9 elements, in the next step, an integer variable i is declared, that uses two for loop to print the value in the given order.

• In the first for loop, it starts from 0 and ends when its value less than 9, and prints the array value.
• In the second for loop, it starts from 9 and ends when the index value equal to 0, and prints the array value in reverse order.