Type in "y=2x" in the google search bar. A graph will pop up and should help you. I'm sorry I cant be of more assistance. Hope this helps! ^_^
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Simple procedure :
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Answer: the incubation time that separates the bottom 2.5% from the rest of the incubation times is 24.96 days.
Step-by-step explanation:
Suppose the incubation times are approximately normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = incubation times.
µ = mean time
σ = standard deviation
From the information given,
µ = 23 days
σ = 1 day
The probability value for the incubation time that separates the bottom 2.5% from the rest of the incubation times would be (1 - 2.5/100) = (1 - 0.025) = 0.975
Looking at the normal distribution table, the z score corresponding to the probability value is 1.96
Therefore,
1.96 = (x - 23)/1
x = 1.96 + 23
x = 24.96
Answer:
750
300
390, 570
120,750
2.28
15.87
Step-by-step explanation:
