Answer:
x = 5
Step-by-step explanation:
We have: The sum of the measures of angle M and angle R is 90°
M + R = 90°
M = (5x + 10)°
Plug M into (1)
the equation: (5x + 10)° + R = 90° (2)
R=55° into (2)
(5x + 10)° + 55° = 90°
5x + 10 + 55 = 90
5x + 65 = 90
5x = 25
x = 5
Answer:
part a: 5
part b: no, ABC is not an equilateral triangle
Step-by-step explanation:
part a: if you do the distance formula for points A and B, you get 5
part b: using the distance formula again, points A to B and points A to C are both 5, but points B to C is 6, therefore it's not equilateral because all the sides have to be the same length
Simplify the following:
(3 sqrt(2) - 4)/(sqrt(3) - 2)
Multiply numerator and denominator of (3 sqrt(2) - 4)/(sqrt(3) - 2) by -1:
-(3 sqrt(2) - 4)/(2 - sqrt(3))
-(3 sqrt(2) - 4) = 4 - 3 sqrt(2):
(4 - 3 sqrt(2))/(2 - sqrt(3))
Multiply numerator and denominator of (4 - 3 sqrt(2))/(2 - sqrt(3)) by sqrt(3) + 2:
((4 - 3 sqrt(2)) (sqrt(3) + 2))/((2 - sqrt(3)) (sqrt(3) + 2))
(2 - sqrt(3)) (sqrt(3) + 2) = 2×2 + 2 sqrt(3) - sqrt(3)×2 - sqrt(3) sqrt(3) = 4 + 2 sqrt(3) - 2 sqrt(3) - 3 = 1:
((4 - 3 sqrt(2)) (sqrt(3) + 2))/1
((4 - 3 sqrt(2)) (sqrt(3) + 2))/1 = (4 - 3 sqrt(2)) (sqrt(3) + 2):
Answer: (4 - 3 sqrt(2)) (sqrt(3) + 2)
1.) Find the area of the circle:
• Formula: A=pi•r^2
- To find the area of a circle, we need to have the radius, and since the diameter is 2x the length of the radius, the radius is 1/2 of the diameter.
Finding the radius: r=d/2
r=12/2
r = 6.
- Now that we know that r=6, we can substitute it into the formula:
• A=pi•r^2
A=pi•(6)^2
A=113.097
- The area of the circle is 113.097ft.^2. We know that a square foot is $10.50. So, we have 113.097 square feet at $10.50/sq. foot. This means that we will add $10.50 113.097 times. Therefore:
113.097 • 10.50 = 1,187.518
So, total, it will cost $1,187.518
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Answer:
term
a word or phrase used to describe a thing
Coefficient
a number for constant quantity
constant
occurring continuously over a period of time
Algebraic expression
In mathematics, an algebraic expression is an expression built up from integer constants, variables, and the algebraic operations.
