Answer:
87.5%
Step-by-step explanation:
Complete question -
75% of the people who eat at Doug's Diner order fish and 90% of the people who order fish also order fries. Given that 80% of all people who eat at Doug's order fries, what is the probability that a randomly chosen customer orders fries without fish?
Solution
Given
People who order fish at the Doug's Diner = 75%
Out of this 75%, 90% also order fries which means that nearly 67.5% ordered fries with the fish.
Given that, 80% of people dining at Doug's Diner order fries
Then percentage or people who ordered only fires and no fish = 80% - 67.5% = 12.5%
The probability of customers who ordered fish = 100 - 12.5% = 87.5%
Answer:
D, "I will pay $25 for this book."
Step-by-step explanation
Answer: 850
Step-by-step explanation: 6,000 divided by 12 = 500 + 350 = 850
Answer:
b= \frac{1}{2ha} -c
Step-by-step explanation:
you would multiply to remove the variable from the denominator and simplify
The mean is: 7.6
The range is: 7
The median is: 7
The mode is: 5
:)
