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Svet_ta [14]
3 years ago
10

Solve this equation -9h -6 +12h + 40=22.

Mathematics
2 answers:
puteri [66]3 years ago
5 0
-9h -6 +12h + 40=22\\
3h=-12\\
h=-4
natulia [17]3 years ago
4 0
<em></em>12h - 9h = 3h

40 - 6 = 34

3h + 34 = 22

3h = -12

h = -4
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A savings account earns 5% simple interest per year. The principal is $1200. What is the balance after 4 years?
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The formula of the Simple Interest is:
I=PRT
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R for Rate                        (5%=\frac{5}{100} = 0.05)
T for Time in years          (4 years)
I = 1200 × 0.05 × 4
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Add the interest to the principle amount to check the balance
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Equations:

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3 years ago
Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En
Sergio [31]

Answer:

\bold{cot(t) =\dfrac{12}{5}}

Step-by-step explanation:

Given that:

Cosec (t) = -\frac{13}5

for \pi < t < \frac{3 \pi}2

That means, angle t is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

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\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}

But, angle t is in 3rd quadrant, so value of

\bold{cot(t) =\dfrac{12}{5}}

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3 years ago
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