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My name is Ann [436]
3 years ago
14

Find the value of tan theta if sin theta = 12/13 and theta is in quadrant 2

Mathematics
1 answer:
8090 [49]3 years ago
5 0

Answer:

tanΘ = - \frac{12}{5}

Step-by-step explanation:

Using the trigonometric identities

• sin²x + cos²x = 1, hence

cosx = ± √(1 - sin²x )

• tanx = \frac{sinx}{cosx}

given sinΘ = \frac{12}{13}, then

cosΘ = ±  \sqrt{1-(12/13)^2}

Since Θ is in the second quadrant where cosΘ < 0, then

cosΘ = - \sqrt{1-\frac{144}{169} }

         = - \sqrt{\frac{25}{169} } = - \frac{5}{13}

tanΘ = \frac{\frac{12}{13} }{\frac{-5}{13} }

        = \frac{12}{13} × - \frac{13}{5} = - \frac{12}{5}



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