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3 years ago

Make an inference about which fish increased its predicted average population from Year 1 to Year 2.

Mathematics

2 answers:

alexdok [17]3 years ago

7 0

Answer:

B. Trout increased its predicted average population.

Step-by-step explanation:

just did it

galben [10]3 years ago

4 0

Make an inference about which fish increased its predicted average population from Year 1 to Year 2.
All three types of fish increased their predicted average population.
Trout increased its predicted average population.
Bass increased its predicted average population.
None of the fish increased their predicted average population.

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Does anyone know the answer to both of these questions????

atroni [7]

Answer:

c d

Step-by-step explanation:

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3 years ago

A certain brand of jelly beans are made so that each package contains about the same number of beans. The filling procedure is n

pantera1 [17]

Answer:

p=0.063

Step-by-step explanation:

Let X be number of the certain brand of jelly beans that are made so that each package contains about the same number of beans.

X is N(375, 8)

YOu are collecting a sample size of

n = 8

Findings from the sample

$\bar x =370\\$

$H_0: \bar x =375\\H_a: \bar x$

(Left tailed test at 5% level)

Since sample size is small though sigma is known we use Z test, since norm

Mean difference = -5

Std error = $\frac{8}{\sqrt{8} } =2.828$

Test statistic t = mean diference / std error = $\frac{-5}{2.828} \\=-1.768$

df = n-1 =5

p value = 0.063

7 0

3 years ago

The diagram below shows two

LiRa [457]

Answer:

4 cm

Step-by-step explanation:

$\frac{8}{ST} = \frac{4}{2} \\\\ST = 8*2 / 4\\ST = 4$

6 0

2 years ago

2x-10=5x-100 what is the value of x?

Leni [432]

Answer:

Step-by-step explanation: I did a formula to get the answer

2x-10=5x-100

2x=5x-90

I subtracted 100-10 and then got 90

3x=90

3x/3x=90/3

x=30

7 0

3 years ago

Evaluate the following integral using trigonometric substitution

serg [7]

Answer:

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

Step-by-step explanation:

We are given the following integral:

$\int \frac{dx}{\sqrt{9-x^2}}$

Trigonometric substitution:

We have the term in the following format: $a^2 - x^2$ , in which a = 3.

In this case, the substitution is given by:

$x = a\sin{\theta}$

$dx = a\cos{\theta}d\theta$

In this question:

$a = 3$

$x = 3\sin{\theta}$

$dx = 3\cos{\theta}d\theta$

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}$

We have the following trigonometric identity:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

$1 - \sin^{2}{\theta} = \cos^{2}{\theta}$

Replacing into the integral:

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C$

Coming back to x:

We have that:

$x = 3\sin{\theta}$

$\sin{\theta} = \frac{x}{3}$

Applying the arcsine(inverse sine) function to both sides, we get that:

$\theta = \arcsin{(\frac{x}{3})}$

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

8 0

3 years ago