D. The males have a suspected significant high outlier.
The outlier will make the box plot be uneven and this will affect the spread and the center.
I know isn't A, because if anything that would make it more balanced.
I know it isn't B because this would not affect the spread or the center.
I know it isn't C because the question is not asking you to determine the spread and center, just to see if there is anything that would affect them.
I hope this helps!
Answer:
C. x=42
Step-by-step explanation:
16 + 3x + y = 180
126 + 16 + y = 180
y = 38
16 + 3x + 38 = 180
54 + 3x = 180
3x = 126
x=42
Answer:
3/4
Step-by-step explanation:
A: students present
B: students on time
P(all students present and on time) = P(A and B) = 3/10
P(all students present) = P(A) = 2/5
P(A and B) = P(A).P(B|A) where P(B|A) is the probability of everyone being on time given that everyone is present
So P(B|A) = P(A and B) /P(A) = 3/10 ÷ 2/5 = 3/10 * 5/2 = 15/20 which can be reduced to 3/4 by dividing numerator and denominator by 5
