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lutik1710 [3]
2 years ago
13

Plssssssssssssssssssssssssssss

Mathematics
2 answers:
pychu [463]2 years ago
6 0
The answer is D)2275
yawa3891 [41]2 years ago
5 0

Answer:

D) 2275

Step-by-step explanation:

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Help (easy question)<br> *attachment below*
JulsSmile [24]

Answer:

total ground and wall angle is 90°

beam angle with ground= 51

beam angle with wall =39

because total angle=angle with ground + angle with wall

angle with wall=total angle-angle with ground

angle with wall= 90-51=39

8 0
3 years ago
If you split a right angle with a ray going through the middle of the right angle, the two angles formed will be ______. Select
Tom [10]

Answer:

Complementary

Step-by-step explanation:

To be complementary, your two angles need to add up to 90 degrees

a right triangle is already 90 degrees so if you cut it through the middle they'd form complementary angles

8 0
3 years ago
Read 2 more answers
Equivalent expression for (x+6)-5+9
Bumek [7]

Answer:

x + 10

Step-by-step explanation:

(x + 6) - 5 + 9 \\  = x + 6 + 4 \\  = x + 10

7 0
3 years ago
What's the difference between 6z and z6
Airida [17]
Simple..

there is a major difference between 6z and z^{6}

6z means: 6 times z

and

z^{6} means: z to the power of 6(z*z*z*z*z*z)

An example...

make z=2...plug n chug..

6z----> 6(2)=12
and
z^{6}--->2^{6}=64

As you can see..there is a major difference.

Thus, your answer.
4 0
3 years ago
3x + ky = 8
sattari [20]

Answer:

(a): <u>x</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>ky</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

<u>(</u><u>b</u><u>)</u><u>:</u><u> </u><u>k</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u>

Step-by-step explanation:

Let: 3x + ky = 8 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em>

x - 2 ky = 5 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em>

<em> </em>Then multiply <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em><em> </em>by 2:

→ 6x + 2ky = 16, let it be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em>

Then <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>+</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em><em>:</em>

<em>{ \sf{(6  + 1)x + (2 - 2)ky = (16  +  5)}} \\ { \sf{7x = 21}} \\ { \sf{x = 3}}</em>

<em>T</em><em>h</em><em>e</em><em>n</em><em> </em><em>k</em><em>y</em><em> </em><em>:</em>

{ \sf{2ky = 3 - 5}} \\ { \sf{ky =  - 1}}

{ \bf{y =  \frac{1}{2} }} \\ { \sf{ky =  - 1}} \\ { \sf{k =  - 2}}

4 0
3 years ago
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