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k0ka [10]
2 years ago
9

Find the surface area of the rectangular prism with the following

Mathematics
2 answers:
Ira Lisetskai [31]2 years ago
8 0
A = L x W x H

A = 4 x 8 x 3

A = 96
svetoff [14.1K]2 years ago
5 0

Answer:

96=4*3*8

Step-by-step explanation:

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FrozenT [24]
How long will she take to what ?

3 0
3 years ago
Find the x- and y-intercepts of the parabola y=x2+10x+4
Nuetrik [128]

Answer:

x-intercepts: -5 +/-\sqrt{21}. y-intercept: 4

Step-by-step explanation:

For x-intercepts use the quadratic equation

x= (-b +/-\sqrt{b^2-4ac} )/2a

Fill in your values:

x= (-10 +/-\sqrt{100-16} )/2

And solve

x=-5 +/- \sqrt{21}

For y-intercepts set x=0 and solve. In this case, setting x= 0 gives you y=4.

6 0
2 years ago
Help I WILL GIVE BRAINLIEST
const2013 [10]

Answer:

16.6

Step-by-step explanation:

8 0
3 years ago
A scale on a map shows that 2 inches equals 25 miles. How many miles is represented by 1/4 inch on the map?
FinnZ [79.3K]
3.125

to get this answer you divide 25 by 2, then divide that by 4, which equals 3.125

good luck hope I helped:)
8 0
3 years ago
Does anyone know how to do this?? Help please!!!!
Doss [256]

Answer:

When we have a rational function like:

r(x) = \frac{x + 1}{x^2 + 3}

The domain will be the set of all real numbers, such that the denominator is different than zero.

So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.

Then we need to solve:

x^2 + 3 = 0

x^2 = -3

x = √(-3)

This is the square root of a negative number, then this is a complex number.

This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.

D: x ∈ R.

b) we want to find two different numbers x such that:

r(x) = 1/4

Then we need to solve:

\frac{1}{4} = \frac{x + 1}{x^2 + 3}

We can multiply both sides by (x^2 + 3)

\frac{1}{4}*(x^2 + 3) = \frac{x + 1}{x^2 + 3}*(x^2 + 3)

\frac{x^2 + 3}{4} = x + 1

Now we can multiply both sides by 4:

\frac{x^2 + 3}{4}*4 = (x + 1)*4

x^2 + 3 = 4*x + 4

Now we only need to solve the quadratic equation:

x^2 + 3 - 4*x - 4 = 0

x^2 - 4*x - 1 = 0

We can use the Bhaskara's formula to solve this, remember that for an equation like:

a*x^2 + b*x + c = 0

the solutions are:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

here we have:

a = 1

b = -4

c = -1

Then in this case the solutions are:

x = \frac{-(-4) +- \sqrt{(-4)^2 - 4*1*(-1)} }{2*(1)} = \frac{4 +- 4.47}{2}

x = (4 + 4.47)/2 = 4.235

x = (4 - 4.47)/2 = -0.235

5 0
3 years ago
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