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Bingel [31]
3 years ago
11

Buy 6 mangoes and get 2 free $2.00 per mango (a) Robin purchased $36.00 worth of mangoes. How many free mangoes did Robin get? (

b) How many mangoes did he get all together? (c) Peter also bought mangoes. He received 40 mangoes. How much did Peter pay?
Mathematics
1 answer:
mylen [45]3 years ago
4 0

Answer:

A.) 6

B.) 24

C.) $60

Step-by-step explanation:

Given that :

Cost of Mango = $2

Purchase of 6 mangoes earns 2 free mangoes

(a) Robin purchased $36.00 worth of mangoes.

How many free mangoes did Robin get?

$36 / price per Mango

$36 / $2 = 18 mangoes

18 / 6 = 3

Hence, free mangoes (3 * 2) = 6 free mangoes

(b) How many mangoes did he get all together?

18 mangoes + 6 mangoes = 24 mangoes

(c) Peter also bought mangoes. He received 40 mangoes. How much did Peter pay?

Set of mangoes purchased:

40/ (6 + 2) = 40/8 = 5 sets of mangoes

Hence, amount paid :

2 * 6 * 5 sets

$60

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!!HELP!! algebra two!! multiply and combine like terms to write as the sum of difference of monomials!! a-i !!!explanation, if p
vazorg [7]

Answer:

a. 10a + 8a²

c. 12z + 3z²

e. -20 + x + x²

g. -64 + 9z⁴

i. y¹⁰⁰¹ + 8y¹³²⁰⁰

Step-by-step explanation:

According to the Six Exponential Rules, whenever you divide terms, you subtract the exponents, and of course whenever you multiply terms, you add the exponents.

a. The variables have an invisible degree term of 1, so when multiplied, you get 8a².

c. ⅛ of 24 and 96 means dividing both numbers by its multiplicative inverse, which is 8: ⅛[24] → 24 ÷ 8; 3; ⅛[96] → 96 ÷ 8; 12. Then of course, you still have to follow the exponential procedure.

e. This is just like the Quadratic Equation, y = <em>Ax² + Bx + </em><em>C</em>. All you have to do is do what I like to call FOIL:

F - Multiply the first terms in each set of parentheses FARTHEST TO THE LEFT

O [Outermost] - Multiply the first term in the first set of parentheses FARTHEST TO THE LEFT by the last term in the second set of parentheses FARTHEST TO THE RIGHT

I [Innermost] - Multiply the last term in the first set of parentheses FARTHEST TO THE RIGHT by the first term in the second set of parentheses FARTHEST TO THE LEFT

L - Multiply the last terms in each set of parentheses FARTHEST TO THE RIGHT

Doing this will give you the above answer.

g. See explanation letter <em>e</em><em>.</em>

i. Now, as I mentioned before, when you multiply terms, you add the exponents. In addition, that decimal in the far right corner, is equivalent to ⅛, and ⅛ of 8 is 1, so we know that 1 is our INVISIBLE coefficient next to the <em>y</em><em>,</em><em> </em>then you just add 1 to 1000 in the exponents because of the invisible degree of 1.

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

**I have a video that talks about the Six Exponential Rules. It is titled "Six Exponential Procedures". Go check out the channel to watch it and gain more assistance.

4 0
3 years ago
Caden states that n^2 +3n + 2n is an equivalent expression to 6n. Why is Caden's statement incorrect?
malfutka [58]
\begin{gathered} \text{The simplification of n}^2+3n+2n\text{ is:} \\ i)n^2+5n \\ By\text{ collecting common term, this can be written in form of:} \\ ii)\text{ n(n+5)} \end{gathered}

Thus, options A and D hold, from the simplifications above.

Let's consider the validity of the remaining options provided.

\begin{gathered} \text{For option B)} \\ \text{substitute for n=1 into the expression n}^2+3n+2n,\text{ we have} \\ 1^2+3(1)+2(1)=1+3+2=6 \\ \text{substitute for n=1 into the expression 6n, we have} \\ 6(1)=6 \\ \text{Thus, the expression n}^2+3n+2n\text{ is equivalent to 6n, for n=1} \end{gathered}\begin{gathered} \text{For option C)} \\ \text{The expression n}^2+3n+2n\text{ does not simplify to 7n} \end{gathered}\begin{gathered} \text{For option E)} \\ \text{substitute for n=4 into the expression n}^2+3n+2n,\text{ we have:} \\ 4^2+3(4)+2(4)=16+12+8=36 \\ \text{substitute for n=6 into the expression 6n, we have:} \\ 6(4)=24 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=4} \end{gathered}\begin{gathered} \text{For option F)} \\ \text{substitute for n=3 into the expression n}^2+3n+2n,\text{ we have:} \\ 3^2+3(3)+2(3)=9+9+6=24 \\ \text{substitute for n=3 into the expression 6n, we have:} \\ 6(3)=18 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=3} \end{gathered}

Hence, the correct options that apply are options A, D, E and F

7 0
1 year ago
Sam has $2.25 in quarters and dimes, and the total number of coins is 12. How many quarters and how many dimes?
a_sh-v [17]
N₁*$0.10 + n₂*$0.25 = $2.25

n₁ + n₂ = 12

-----------

This means that:

n₁ = 12 - n₂

And:

(12 - n₂)*$0.10 + n₂*$0.25 = $2.25

12*$0.10 - n₂*$0.10 + n₂*$0.25 = $2.25

$1.20 + n₂*$0.05*(5-2) = $2.25

$1.20 + n₂*$0.05*3 = $2.25

$1.20 + n₂*$0.15 = $2.25

n₂*$0.15 = $2.25 - $1.20

n₂*$0.15 = $1.05

n₂ = ($1.05)/($0.15)

n₂ = 7

If n₂ = 7:

n₁ + 7 = 12

Therefore, n₁ = 5.

---------

Answer:

5 dimes and 7 quarters.
8 0
3 years ago
Read 2 more answers
2x+3-3=-6<br><br><br><br> x=3 ? Solve
ivann1987 [24]

2(x)+3-3=-6\\2(3)+3-3=-6\\6+3-3=-6\\6=-6\\

x\neq 3

As we can see, x cannot be equal to 3 as 6 cannot equal -6.

I hope I've helped! :)

6 0
2 years ago
360 km is 24% of blank kilometers
Ede4ka [16]

Answer:

86.4km

Step-by-step explanation:

you do 360*24% then you'll get the answer


4 0
3 years ago
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