Answer:
See explanation
Step-by-step explanation:
<u> ASA Postulate (Angle-Side-Angle):</u>
If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.
Consider triangles XYB and ZYA. In these triangles
- ∠X≅∠Z (given)
- XY≅ZY (given)
- ∠Y is common angle
By ASA Postulate, triangles XYB and ZYA are congruent. Congruent triangles have congruent corresponding sides, so
BX≅AZ
15=3b
15/3 = 3b/b
5= b
Isolate the variable by diving 3 on both sides
Answer:
Step-by-step explanation:
a = 5
r = -5
n = 9
t_9 = a r^(n - 1)
t_9 = (-1)^n*5 (-5) ^ 8
t_9 = (-1)^9 * 5 * (-5) ^8
t_9 = -1 ( 1953125)
t_9 = - 1953125
Answer:
8 square units
Step-by-step explanation:
The figure is a trapezoid. The area of it is given by the formula ...
A = (1/2)(b1 +b2)h
where b1 and b2 are the lengths of the parallel bases and h is the distance between them.
Your figure shows the base lengths to be 5 and 3, and their separation to be 2. Filling the numbers in the formula, we have ...
A = (1/2)(5 +3)(2) = (1/2)(8)(2) = 4·2 = 8
The area of the figure is 8 square units.
_____
The right-pointing arrows on the horizontal lines identify those lines as being parallel. The right-angle indicator and the 2 next to the dotted line indicate the perpendicular distance between the parallel lines is 2 units.
Answer:
The new volume is 20litres
Step-by-step explanation:
This problem bothers on the expansion of gases
According to Boyle's law
The volume of a given mass of gas at constant temperature is inversely proportional to the pressure
P∝1/v
Pv= constant
Given data
P1= 1.5atm
v1 = 10 litter
P2=0.75atm
v2=?
Applying P1v1= P2v2
v2= P1v1/P2
v2= 1.5*10/0.75
v2= 15/0.75
v2= 20litres
