Answer:
Step-by-step explanation:
The answer is 32.7 b so the answer is 105 over 10
Evaluating the given sequence, it is evident that the next number is twice the number prior to it. Thus, the given is a geometric sequence with first term (a1) equal to 1 and common ratio of 2. The geometric series may be calculated by the equation,
Sn = a1 x (1 - r^n) / (1 - r)
where Sn is the sum of n terms in this case, n = 11.
Substituting the known values,
<span> Sn = 1 x (1 - 2^11) / (1 - 2) = 2047
</span>
Thus, S11 is 2047.
The conjecture is each term is the corresponding Roman numeral of the precious term
12 ^3 and 11^3 haven't got the same base so the rules of exponents do not apply.
Bases have to be the same:- for example 12^3 * 12*3 = 12 ^(3+3) = 12^6
