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3 years ago

Show a way to count from 170 to 410 using tens and hundreds. circle at least one benchmark number.

Mathematics

1 answer:

WITCHER [35]3 years ago

6 0

By counting cause you can find your answer duh

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PLEASE HELP!!!!!!!!!!!

scoundrel [369]

Answer:

the triangle is translated 2 units up, and is reflected across the x axis

Step-by-step explanation:

6 0

3 years ago

Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive

PtichkaEL [24]

Looks like the PMF is supposed to be

$\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}$

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

$\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65$

Next,

$\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25$

$\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5$

$\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2$
$\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5$
$\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}$

If $Y=X^2+1$ , then $X^2=Y-1\implies X=\sqrt{Y-1}$ , where we take the positive root because we know $X$ can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that $Y$ can take on the values $1^2+1=2$ , $2^2+1=5$ , and $5^2+1=26$ . At these values of $Y$ , we would have the same probability as we did for the respective value of $X$ . That is,

$\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}$

Part (5) is incomplete, so I'll stop here.

8 0

3 years ago

it takes approximately 1200 KG of coal to produce the energy needed to make 1 kg of aluminum is a single soda can requires 15 g

Pavel [41]

see so,1200 kg of coal=1kg of aluminum

if 1 soda can needs 15g of aliminium so

1200/15=80kg coal will be needed for 1 can of soda.

4 0

3 years ago

If Max had a 12 ounce bottle and his friend drank 1 ounce how much would he left of ounces

yKpoI14uk [10]

Answer:

11 ounces

Step-by-step explanation:

12-1=11

7 0

4 years ago

Read 2 more answers

What are the solutions of -1 ≤ x – 3 < 4

cricket20 [7]

Answer:

2 ≤ x < 7

Step-by-step explanation:

-1 ≤ x – 3 < 4

Add 3 to each side

-1+3 ≤ x – 3+3 < 4+3

2 ≤ x < 7

7 0

3 years ago