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sergejj [24]
3 years ago
11

Show a way to count from 170 to 410 using tens and hundreds. circle at least one benchmark number.

Mathematics
1 answer:
WITCHER [35]3 years ago
6 0
By counting cause you can find your answer duh
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How is multiplication using partial products different from multiplication using regrouping?
klio [65]
Partial products is breaking down every number in multiplication and adding them. Regrouping is grouping number them adding them.They are alike because they both involve breaking down the numbers and adding them.  They are different because one is taking all the numbers broken down, while the other is just a couple of the number.
5 0
4 years ago
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Which mixed number is equivalent to the improper fraction?<br> 14/9
hodyreva [135]

Answer: 1 5/9 (one and five-ninths)

3 0
3 years ago
HELP ME PLEASE WILL PICK BRAINLYEST
Ronch [10]
Here's one way to do it.

AB ≅ AC . . . . . . . . . . given
∠BAY ≅ ∠CAY . . . . given
AY ≅ AY . . . . . . . . . . reflexive property
ΔBAY ≅ ΔCAY . . . .. SAS congruence
XY ≅ XY . . . . . . . . . . reflexive property
∠AYB ≅ ∠AYC . . . . CPCTC
BY ≅ CY . . . . . . . . . . CPCTC
ΔXYB ≅ ΔXYC . . . .. SAS congruence

Therefore ...
∠XCY ≅ ∠XBY . . . . CPCTC
3 0
3 years ago
Find the missing side length of the right triangle shown. Round to the nearest tenth, if
Delvig [45]

Answer:

? = 26 in

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

?² = 24² + 10² = 576 + 100 = 676 ( take the square root of both sides )

? = \sqrt{676} = 26

4 0
3 years ago
Read 2 more answers
Write an equation of the perpendicular bisector of the segment with endpoints G 9,8       and H 3,2      .
Norma-Jean [14]

Answer:

y = -x + 11

Step-by-step explanation:

The equation of a straight line is is given by:

y = mx + b; where m is the slope and b is the y intercept

The equation of the line joining G(9, 8) and H(3, 2) is given as:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-8=\frac{2-8}{3-9}(x-9)\\\\y-8=x-9\\\\y=x-1

The perpendicular bisector of the line joining G(9, 8) and H(3, 2) is perpendicular to the line joining G(9, 8) and H(3, 2) and passes through the midpoint of line joining G(9, 8) and H(3, 2).

Let (x, y) be the midpoint of the line joining G(9, 8) and H(3, 2). Hence:

x = (9 + 3)/2 = 6

y = (8 + 2)/2 = 5

The midpoint = (6, 5)

Two lines are perpendicular if the product of their slopes is -1.

The line joining G(9, 8) and H(3, 2) has a slope of 1, hence, the slope of the perpendicular bisector would be -1.

This means that the perpendicular bisector has a slope of -1 and passes through (6, 5). Using:

y-y_1=m(x-x_1)\\\\y-5=-1(x-6)\\\\y-5=-x+6\\\\y=-x+11

The equation of the perpendicular bisector is y = -x + 11

8 0
3 years ago
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