Question and answer in picture

Mathematics

2 answers:

Andrews [41]3 years ago

5 0

Answer:

i think the answer is B but don't take my word for it

amid [387]3 years ago

3 0

The answer is (B) because the x axis goes on the top and the y axis goes to the bottom and plus the 2 is on the negative side.... hope I been very helpful if can u plz give me five stars

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Find the sum of a finite geometric series. The Smiths spent $2,000 on clothes in a particular year. If they increase the amount

boyakko [2]

$\bf \stackrel{\textit{first year}}{2000}~~,~~\stackrel{\textit{second year}}{2000+\stackrel{\textit{10\% of 2000}}{\frac{2000}{10}}}\implies 2200$

now, if we take 2000 to be the 100%, what is 2200? well, 2200 is just 100% + 10%, namely 110%, and if we change that percent format to a decimal, we simply divide it by 100, thus $\bf 110\%\implies \cfrac{110}{100}\implies 1.1$ .

so, 1.1 is the decimal number we multiply a term to get the next term, namely 1.1 is the common ratio.

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\a_1=2000\\r=1.1\\n=4\end{cases}\\\\\\S_4=2000\left[ \cfrac{1-(1.1)^4}{1-1.1} \right]\implies S_4=2000\left(\cfrac{-0.4641}{-0.1} \right)\\\\\\S_4=2000(4.641)\implies S_4=9282$

7 0

3 years ago

Pablo simplified the expression (2 Superscript negative 4 Baseline) Superscript negative 2 as shown. (2 Superscript negative 4 B

Lorico [155]

Answer:

He should have found 8 as the exponent, not –8.

Step-by-step explanation:

im doing a unit test

8 0

3 years ago

Read 2 more answers

3. A certain 50 cm spring will stretch (in

garik1379 [7]

Complete Question

A certain 50 cm spring will stretch (in cm) one fifth the weight (in kg) attached to it. How long will the spring be if a 35 kg weight is attached to it

Answer:

The value is $L_w = 57 \ cm$

Step-by-step explanation:

The length of the spring is $L = 50 \ cm = 0.5 \ m$

The mass attached to it is $w = 35 \ kg$

Generally given from that the spring will stretch one fifth of the weight (in kg)attached to it , it then means that the new length of the spring whenever a weight is attached to it is mathematically represented as

$L_w = L + \frac{W}{5}$