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laiz [17]
4 years ago
11

So far you have mostly worked with equations. There are special types of equations, called functions, that have exactly one outp

ut for every possible input into the equation. An example of this in the real world is the amount of money you are charged at a store: the input is the item you are purchasing, and the output is the money you are charged. Individual items have one price, so this is an example of a function. Can you think of any other examples of functions? Why might this type of equation be useful?
Mathematics
2 answers:
BaLLatris [955]4 years ago
6 0

Answer:

There is no certain answer because answer is in words. In mathematical terms

consider f(x) =x + 2, f(x)= x² + 3x +2,

You have to write polynomials having single variable having any degree will be a function.


Step-by-step explanation:

Real life example :

There are thousands of examples and i am writing few of them.

1. From a set of parents P_{1}, P_{2},P_{3} and P_{4} each having a single child either son or daughter is a function S_{1},D_{1},[S_{2} D_{2}], D_{4}. which is represented as a function , each having a unique outcome[P_{1}⇒ S_{1}], [P_{2}⇒ D_{1}],[P_{3}⇒ {S_{2} D_{2}], [P_{4}⇒ D_{4}]

2. There are different kind of employees in an office or in a system ,or in a country working in government or private sector ranging in Different Grades. Each employee get salary according to rank they possess or the qualification they have.

3. Consider Food you eat and specific nutrients they possess. So, [ Type of Food⇒Nutrients contained in them] are functions.

This type of equation is useful because for each of these examples we can make different equations .Let me make one for you.

Suppose you eat Egg. Represent it by y.it has 4 nutrients (a)Protein (b) Riboflavin (c) Selenium (d) Vitamin.

So if i will write it in terms of equation we can write

y =x²+x+2 [ Considering x=1,we get number of nutrients possessed by egg]

So,by this way we can say these equations are useful.

amid [387]4 years ago
4 0
Can you think of any other examples of functions?

<em>Yes! Like putting a check in the bank, that is the input- and then the money you take is the output. You can even use food to compare input and output! Ingredients are the input, and the final dish/dessert is the output. If you wanted something more mathematical, you can use a graph to find the input and output. If you know a few points, you can create a whole line of x and y points, where x= input and y=output. You can also consider getting gas for your car, the money is the input, and the gas (in return) is the output. <== these are just a few examples. 
</em>
Why might this type of equation be useful? 

When you are trying to find the points for a line or looking for the unit price for something, functions can be very useful! You can find what y would be when x equals 1, 2, 3, 4, etc. I know I use this all the time! For example, trying to find the best price for something in the grocery store. There are a lot of options, and if you find the unit price with functions, it makes it easier to get the best deal.

I hope this helps!
~kaikers
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3 years ago
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Leto [7]

Answer:

See Below.

Step-by-step explanation:

Remember that the maximum account balance Ebony had was $400.

We can see that her bank balance first reached $400 on Day 4 and continued until Day 8.

Part A)

Since the maximum amount is $400, it is whenever the graph reaches (and stays) at its maximum, or the highest points on the graph.

We can see that at around Day 4, she first reached her maximum of $400 since that is the highest point of the graph.

And this continues until approximately Day 8.

Therefore, Ebony first reached $400 on Day 4 and stayed at $400 until Day 8.

Part B)

Refer above. The explanation is the same.

Part C)

Jade is says that the amount Ebony is depositing per day from Days 0 to 4 is the same as the amount Ebony is withdrawing per day from Days 8 to 12.

We also know that Day 12 is when Ebony’s account first reached 0.

Essentially, Jade is saying that the <em>slope</em> of the line from Days 0 to 4 is <em>the same</em> as the <em>slope</em> of the line from Days 8 to 12.

Ignoring the negative, we can immediately see that this is not true without calculating.

This is because the slope of the line from Days 8 to 12 is much steeper than than slope of the line from Days 0 to 4.

So, the two slopes are not equal since they are not the same steepness.

Therefore, this means that from Days 8 to 12, Ebony withdrew money at a <em>faster rate per day</em> than she had been depositing from Days 0 to 4.

Hence, Jade’s statement cannot be true.

3 0
3 years ago
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I need someone to help me do this, see attached documents for the questions
Brilliant_brown [7]

Answer:

<u><em>1.) 20.2</em></u>

Step-by-step explanation:

1.) You need to use the distance formula:

d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Find the distance of A to B first:

(-2,2)(3,2)\\\\\sqrt{(3+2)^2+(2-2)^2}\\\\\sqrt{(5)^2+(0)^2}\\\\\sqrt{25} =5

B to C:

(3,2)(-1,-5)\\\\\sqrt{(-1-3)^2+(-5-2)^2}\\\\\sqrt{(-4)^2+(-7)^2}\\\\\sqrt{16+49}\\\\\sqrt{65} =8.06=8.1

C to A:

(-1,-5)(-2,2)\\\\\sqrt{(-2+1)^2+(2+5)^2}\\\\\sqrt{(-1)^2+(7)^2}\\\\\sqrt{1+49}\\\\\sqrt{50}=7.07=7.1

Add distances to find the perimeter:

5+8.1+7.1=20.2

2.) Part A:

You need to use the mid-point formula:

midpoint=(\frac{x_{1}+x_{2}}{2} ,\frac{y_{1}+y_{2}}{2} )

(3,2)(7,11)\\\\(\frac{3+7}{2},\frac{2+11}{2})\\\\(\frac{10}{2},\frac{13}{2})\\\\m=(  5,6.5)

Part B:

1. Use the slope-intercept formula:

y=mx+b

M as the slope, b the y-intercept.

Find the slope of the two points A and B using the slope formula:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} =\frac{rise}{run}

Insert slope as m into equation.

Take point A as coordinates (x,y) and insert into the equation. Solve for the intercept, b:

(y)=m(x)+b

Insert the value of b into the equation.

2.  Use the mid-point coordinate. Take the slope.

If you need to find the perpendicular bisector, you will take the negative reciprocal of the slope. Switch the sign and flip it. Ex:

\frac{1}{2} =-\frac{2}{1}=-2\\

Insert the new slope into the slope-intercept equation as m.

Take the mid-point coordinate as (x,y) and insert into the equation with the new points. Solve for b.

Insert the value of b.

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