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Brut [27]
3 years ago
13

You have $1000 to invest in two different accounts. In order to save the money you need for college, you need to average 6.6 per

cent interest. If the two accounts pay 5 percent and 7 percent interest, how much should you invest in each account?

Mathematics
1 answer:
inysia [295]3 years ago
6 0
Let x dollars be your investment at 7%;

then the investment at 3% is the rest (1000-x) dollars.


The total interest equation is

0.07x + 0.03*(1000-x) = 0.061*1000.


Express x and calculate

x = %280.061%2A1000-0.03%2A1000%29%2F%280.07-0.03%29 = 775.


ANSWER. $700 is the 7% investment; the rest, (1000-775) = 225 dollars is the 3% investment.
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6 0
3 years ago
(1) a) 5270 cl= ? dal
Ivanshal [37]

Answer:

Check below

Step-by-step explanation:

1) These metric volume units can be easily converted by dividing or multiplying by 10 and its multiple. Like this: each step up on the ladder multiply by 10. Each step down divide by 10

a)5270 \:cl=527\:dl\\b)kl=5.3 \times 10=530 hl\\c)58000ml=5.8 dal =(\frac{58000}{10000})\\d)0.39 dal=3.9 l\\e)7.8 dal=780 dl\\f)57.2 ml=5.72 cl.

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Bear in mind these useful relations:

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a) 3.7 l=3700 cm^{3}\\b)29.6 dm^{3}\\29.6 dm^{3} \rightarrow 29.6\times10^{3} cm^3=29.6\times10^{3} ml = 29.6\times10^{2} cl \:or\:2960 cl\\c)8.1l=8100 cm^{3}\\d)5l=\frac{5}{10^{-3}} m^{3}\\e)5.2 cl=52ml=52 cm^{3}=52\times10^{3}=52000 \:mm^{3}\\f)375 ml=375 cm^{3}\\g) 1300 cm^{3}=1300 ml=13 dl\\h) 8.6 ml= 8.6 cm^{3}\times\: 10^{3}=8600 mm^{3}\\i) 51.8\times 10^{11} l \rightarrow 51.8\times 10^{-11}km^{3}

6 0
3 years ago
-x/3 &gt;5 the sign is supposed to be greater than or equal to but I don’t have that option
9966 [12]

Answer:

x ≤ -15

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-x / 3 ≥ 5

multiply by 3

-x ≥ 15

add x to both sides and subtract 15 from both sides

-15 ≥ x or x ≤ -15

4 0
3 years ago
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