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Natalija [7]
2 years ago
9

A car traveled at an average rate of 51 miles per hour on one highway. It then traveled at an average rate of 71 miles per hour

on a second highway. If the car traveled a total of 508 miles in 8 hours, how many miles were driven on the first highway?
Mathematics
1 answer:
grandymaker [24]2 years ago
3 0
3 miles
51 \times 3 = 153
71 \times 5 = 355
355 + 153 = 508
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Answer:

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Step-by-step explanation:

From analysis the   car traveling at 30 km/h has greater kinetic energy

we can deduce it from the expression of kinetic energy which is

KE=\frac{1}{2} mv^2

Assuming the mass m= 1 kg

 

For the 30 km/h

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For the 15 km/h

KE=\frac{1}{2}*2*15^2 \\\\ KE=\frac{1}{2}*2*225 \\\\\ KE=\frac{1}{2}*450 J\\\\\ KE=225 J

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3 years ago
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3 years ago
I need help on this question please and thank you!
Kay [80]

Answer:

The 2nd one.

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1 year ago
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The mathematical expression is |5y|+8/x

3 0
2 years ago
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forsale [732]

Answer:  She paid $66.33

Step-by-step explanation:

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Overall, she paid 66.33.

6 0
2 years ago
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