<u>Answer:</u>
Value of cosθ is ±√7/3 .
<u>Step-by-step explanation:</u>
According to the Question , value of :

And , we know the identity of sine and cosine as ,
<u>Using</u><u> </u><u>,</u><u> </u><u>this</u><u> </u><u>ident</u><u>ity</u><u> </u><u>we</u><u> </u><u>have</u><u> </u><u>;</u><u> </u>

Now , here since θ is in 2nd quadrant and in 2nd quadrant cos is negative . Hence ,the value of cos will be :
Answer: (3a + 1) (a + 3)
Step-by-step explanation:
<u>Concept:</u>
Here, we need to know the idea of factorization.
It is like "splitting" an expression into a multiplication of simpler expressions. Factoring is also the opposite of Expanding.
<u>Solve:</u>
Given = 3a² + 10a + 3
<em>STEP ONE: separate 3a² into two terms</em>
3a
a
<em>STEP TWO: separate 3 into two terms</em>
3
1
<em>STEP THREE: match the four terms in ways that when doing cross-multiplication, the result will give us 10a.</em>
3a 1
a 3
When cross multiply, 3a × 3 + 1 × a = 10a
<em>STEP FOUR: combine the expression horizontally to get the final factorized expression.</em>
3a ⇒ 1
a ⇒ 3
(3a + 1) (a + 3)
Hope this helps!! :)
Please let me know if you have any questions
Answer:
<u>The answer is option C. 6a-7</u>
Step-by-step explanation:
Given that
5(3a-1)-2(3a-2)=3(a+2)+v
Solve for v
∴ v = 5(3a-1)-2(3a-2) - 3(a+2)
∴ v = 15a - 5 - 6a + 4 - 3a - 6
∴ v = 15a - 6a - 3a - 5 + 4 - 6
∴ v = 6a - 7
<u>So the answer is option C. 6a-7</u>
Construct the perpendicular bisector of ST