The mean exam score for the first group of twenty examinees applying for a security
job is 35.3 with a standard deviation of 3.6.
The mean exam score for the second group of twenty examinees is 34.1 with a
standard deviation of 0.5. Both distributions are close to symmetric in shape.
Use the mean and standard deviation to compare the scores of the two groups.
Answer:
136.8
Step-by-step explanation:
76 percent *180 =
(76:100)*180 =
(76*180):100 =
13680:100 = 136.8
<span>In the exponential growth/decay part, any number to the power of n should be to the power… ... do notmultiply them by each other, leave the bases the same and keep in exponential form .... y=a(b^x) and a is the y intercept, b is the growth or decay factor ... Give the exponential growth model and explain each part. y=(1+r)ⁿ, ...</span><span>
</span>
333
32/50 = 0.64
64% of 520 is 332.8 ... hopefully there isn't .80 of a student somewhere in that school, so 333.
The answer is D. No solution
Work: |-2x-1|=-11
