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Lelechka [254]
3 years ago
10

HELP 10PTS AND BRAINLIESTThe image of a triangle after it has been dilated with a center of dilation at the origin has vertices

at A(12, –6), B(–24, –12), and C. If the pre-image of B, point B, has coordinates of (–18, –9) and the pre-image of C, point C, has coordinates of (–13.5, 18), which statements are true? Check all that apply.
The coordinates of C are (27, 18).
The coordinates of C are (–18, 24).
The scale factor is 1 1/3 .
The scale factor is 1 1/5 .
The scale factor is 3/5.
The coordinates of A are (16, –8).
The coordinates of A are (9, –4.5).
Mathematics
2 answers:
Gala2k [10]3 years ago
8 0

Answer:

C is (-18, 24)

Scale factor 1 1/3

A is (9, - 4 1/2)  *4 1/2 is also 4.5

Step-by-step explanation:

When we take a look at image B (-24, -12) and pre image B (-18, -9),

we can work out the scale factor by

(-24/-18) and (-12/-9) both equal 4/3

So using the scale factor to go from the pre image to the image,

We can find C coordinate by multiplying pre image C by the scale factor.

C is (-13.5 x 4/3) and (18 x 4/3)

C is (-18, 24)

The scale factor is 4/3, which is the mixed numeral of 1 1/3.

To find the pre image of point A we divide the image by the scale factor

A is (12/(4/3)) and (-6/(4/3))

A is (9, - 4 1/2)

Hope this helps,

Cate

Anna007 [38]3 years ago
5 0

Answer:

bcg

Step-by-step explanation:

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Rasek [7]

Answer:

24x^3-30x^2+36x

Step-by-step explanation:

you distribute.

(2x+3)(4x^2-5x+6)

distribute the 2x first

3(4x^2*2x-5x*2x+6*2x)

then simplify

3(8x^3-10x^2+12x)

then distribute again (I'm distributing and multiplying it out in this step)

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3 0
3 years ago
144=12x <br> 45 =4x-27 <br> 2x-2=14 <br> 12x=44-10x does any one kno these questions?
Free_Kalibri [48]

Hello russell6333!

\huge \boxed{\mathfrak{Question} \downarrow}

Solve for x.

  1. 144 = 12x
  2. 45 = 4x - 27
  3. 2x - 2 = 14
  4. 12x = 44 - 10x

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

1) \:  \:  \: 144 = 12x \\  \frac{144}{12}  = x \\ \boxed{ \boxed{  \bf12 = x}}

__________________

2) \:  \:  \: 45 = 4x - 27 \\ 45 + 27 = 4x \\ 72 = 4x \\  \frac{72}{4}  = x \\  \boxed{ \boxed { \bf18 = x }}

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3) \:  \:  \: 2x - 2 = 14 \\ 2x = 14 - 2 \\ 2x = 12 \\ x =  \frac{12}{2}  \\ \boxed{  \boxed{ \bf \: x = 6}}

__________________

4) \:  \:  \: 12x = 44 - 10x \\ 12x + 10x = 44 \\ 22x = 44 \\ x =  \frac{44}{22}  \\  \boxed{\boxed{  \bf \: x = 2}}

__________________

<h3><u>NOTE </u><u>:</u><u>-</u></h3>
  • To solve questions of these sorts, bring all the terms to one side & simplify it leaving x alone in the other side of the equation (other side of the equal to sign). After simplification you'll get the value of x.
  • Remember that the signs & operations will change when you bring a term to the other side of the equation.
  • So, addition will become subtraction, subtraction will become addition, multiplication will become division & division will become multiplication.

__________________

Hope it'll help you!

ℓu¢αzz ッ

8 0
3 years ago
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Helen [10]
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Trying to factor by pulling out :

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Thoughtfully split the expression at hand into groups, each group having two terms :

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               -------------------
Add up the two groups :
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<span>3m-8 is the answer</span>

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