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sergeinik [125]
3 years ago
9

A new site offers a subscription that costs 28.50 for 6 months.what is unit rate price per month? show ur work

Mathematics
1 answer:
Setler79 [48]3 years ago
8 0

Answer:

The answer is 4.75

Step-by-step explanation:

Since six months is 28.50 then 1 month is equal to x

       28.50: 6 months

           x     : 1 month

 After this  you cross multiple so u divide by 6 both side to get 4.75

   6x/6: 28.50/6

   x=4.75

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Soloha48 [4]

Answer:

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4 0
2 years ago
Please help me with the below question.
VMariaS [17]

By letting

y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}

we get derivatives

y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}

y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0

Examine the lowest degree term \left(x^{r-1}\right), which gives rise to the indicial equation,

5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients c_k is

(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}

so that with r = 4/5, the coefficients are governed by

c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}

c) Starting with c_0=1, we find

c_1 = -\dfrac{c_0}5 = -\dfrac15

c_2 = -\dfrac{c_1}{10} = \dfrac1{50}

so that the first three terms of the solution are

\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}

4 0
2 years ago
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Mrac [35]

Answer:

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8 0
3 years ago
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Vilka [71]
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x = 0.265938718
7 0
3 years ago
Can someone plz help me with this one problem plz!!!<br><br> I WILL MARK BRAINLIEST!!!
Digiron [165]

Answer:

(1,6) , (2,7) , (3,8) , (4,9) , (5,10)

Step-by-step explanation:

Given equation: y = x + 5

when x = 1, y = 1 + 5 = 6

(1,6)

when x = 2, y = 7

(2,7)

when x = 3 , y = 8

(3,8)

when x = 4 , y = 9

(4,9)

when x = 5 , y = 10

(5,10)

4 0
2 years ago
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