X = gummy bears, y = jelly beans, z = gobstoppers
x + y + z = 13
x + 2y + 2z = 20
x = 3y
3y + y + z = 13
4y + z = 13
3y + 2y + 2z = 20
5y + 2z = 20
4y + z = 13....multiply by -2
5y + 2z = 20
-----------------
-8y - 2z = -26
5y + 2z = 20
---------------add
-3y = -6
y = 2........2 lbs jelly beans
x = 3y
x = 3(2)
x = 6....6 lbs gummy bears
x + y + z = 13
6 + 2 + z = 13
8 + z = 13
z = 13 - 8
z = 5........5 lbs gobstoppers
so we have : 6 lbs gummy bears (x), 2 lbs jelly beans (y), and 5 lbs gobstoppers (z)
Answer: 0
Step-by-step explanation:
Given that :
Mean score on test = 5
Standard deviation on test = 2
Distribution = normal
The mean value when Converted to a z - distribution :
Zscore = (x - mean) / standard deviation.
Hence z score for the mean score will be :
X = mean score
Zscore = ( 5 - 5) / 2
Zscore = 0 / 2
Zscore = 0
Mean value when Converted to a z distribution will be 0
Answer:
-3
Step-by-step explanation:
Since the - in -7 and the subtraction sign - are the same, you have to group them so now it is + (positive). -10 + 7 = -3
B is the answer how you do good
Answer:
Evaluate using scientific notation.
0.00000068x