For this case we have the following equation:
f (x) = x ^ 2 + bx-49
Deriving we have:
f '(x) = 2x + b
We match zero:
0 = 2x + b
We clear x:
x = -b / 2
The axis of symmetry is at x = 8, therefore:
x = -b / 2 = 8
Clearing b:
b = -2 * (8)
b = -16
Answer:
the value of b is:
b = -16
1/3n * -6 = -2n
1/3n * 27m = 9nm
1/3n* -51p = -17np
-2n + 9nm - 17np
The probability of getting exactly 1 green will be 1/13.
<h3>What is probability?</h3>
The chances of an event occurring are defined by probability. Probability has several uses in games, in business to create probability-based forecasts,
Given data;
No of blue marbles= 5,
No of red marbles=6
No of green marbles=2
Total no of ball = 5+6+2
Total no of ball = 13
The probability of getting one green marble is;
P(G)=1/13
Hence, the probability of getting exactly 1 green will be 1/13.
To learn more about the probability, refer to the link;
brainly.com/question/11234923
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Answer:
33
Step-by-step explanation:
you take the number used the most and that's your mode and you can have multiple but for this problem its 33
Answer:
Kate's possible hourly rate of pay: $34.75
Hours of overtime: 100
Step-by-step explanation:
In order to find Kate's hourly wage, we can set up an equation based on the number of hours she works per week and the estimated number of overtime hours to equal her total pay for the year. If Kate works 36 hours/week and there are 52 weeks in a year, her total hours for one year are: 36 x 52 = 1872. Setting up an equation based on her total earnings of $72,000:
1872x + 100(2x) = 72000, where 'x' is the hourly rate and '2x' is her overtime rate which is double time.
Combine like terms: 1872x + 200x = 72000 or 2072x = 72000
Divide both sides by 2072: 2072x/2072 = 72000/2072
Solve for x: x = $34.75
Kate's hourly rate is estimated at $34.75. We can check to see if this is correct by putting this value back into our original equation:
1872(34.75) + 100(2)(34.75) = 65052 + 6950 = 72002
The answer of $72,002 is very close to $72,000 and the best estimate of Kate's hourly wage and overtime hours.