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ki77a [65]
2 years ago
7

Dean's father, Franco, is 5 times his age. Dean is 8 years older than his sister, Helen. The sum of their ages is 62 years. How

old is each person
Mathematics
1 answer:
lidiya [134]2 years ago
3 0

Answer:

dean = 10

franco = 50

helen = 2

steps

you want to get the age of one of the people first

'is' means equal

'older than' means plus

'sum' means total by adding

d

f = 5d

d = 8 + h

d + f + h = 62

make sure there is 1 letter to solve for

d = 8 + h -> h = d - 8

f = 5d

d = d

d + f + h = 62

d + (5d) + (d-8)

7d - 8 = 62

7d = 70

d = 10

f = 50

h = 2

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9 hours

Step-by-step explanation:

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hram777 [196]
Surface area = 2(ab+bc+ac)
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3 years ago
HELP YOU WILL GET BRAINLIEST
dezoksy [38]

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60π

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7 0
3 years ago
Someone help please!!!!
LUCKY_DIMON [66]

Answer:

x = -2

TU = 4

UB = 2

Step-by-step explanation:

you can add x^2 with 4x+10 and equate it to 6:

x^2 + 4x + 10 = 6

x^2 + 4x + 4

then u can use the roots formula : x = (-b ± √ (b2 - 4ac) )/2a

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5 0
2 years ago
A drawer contains 3 white shirts, 2 blue shirts, and 5 gray shirts. A shirt is randomly
shutvik [7]

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = \frac{1}{4}

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

Here, total number of shirts = 3+2+5 = 10

First of all, let us learn about the formula of an event E:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}

P(First\ White) = \dfrac{3}{10}

Now, this shirt is set aside.

So, total number of shirts left are 9 now.

P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = \frac{1}{4}

4 0
3 years ago
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