Using reliable internet sources, identify three ways we use analog and digital signals in our everyday lives.

An array is sorted (in ascending order) if each element of the array is less than or equal to the next element .

Aleks04 [339]

Answer:

// The program below checks if an array is sorted or not

// Program is written in C++ Programming Language.

// Comments are used for explanatory purpose

//Program Starts here

#include<iostream>

using namespace std;

//Function to check if the array is sorted starts here

int isSorted(int arr[], int count)

{

// Check if arrays has one or no elements

if (count == 1 || count == 0) {

return 1;

}

else

{

// Check first two elements

if(arr[0] >= arr[1])

{

return 0; // Not sorted

}

else

{ // Check other elements

int check = 0;

for(int I = 1; I<count; I++){

if (arr[I-1] > arr[I]) { // Equal number are allowed

check++; // Not sorted

}

if(check==0)

return isSorted(arr, count - 1); //Sorted

else

return 0; // Not sorted

}

// Main Method starts here

int main()

{

int count;

cin<<count;

int arr[count];

for(int I = 1; I<=count; I++)

{

cin>>arr[I-1];

}

int n = sizeof(arr) / sizeof(arr[0]);

if (isSorted(arr, n))

cout << "Array is sorted";

else

cout << "Array is not sorted";

}

8 0

3 years ago

Su now wants to highlight several inventors in her presentation, so she decides to use the underline color option.

Mars2501 [29]

Answer:

1. The home tab

2. Font group

3. The small arrow at the bottom right of the font command group.

4. On "Font" heading (then "All text" subheading)

Explanation:

The following explanation will help Su in accomplishing her task.

1. Go to the home tab;

2. From the home tab, Su will have access to various command groups but in her case, she needs the Font command group.

3. There's a small arrow located at the bottom left of the font command group section; clicking on this arrow will open the font dialogue.

4. On the font dialogue, there are two headings. The "font" heading and the "character spacing" heading.

In her case, she needs the "Font" heading. The font heading also has various subheadings. To access the underline colour option, she needs the "All text" subheading.

See attachment for picture guide.

7 0

3 years ago

Define the Artist class with a constructor to initialize an artist's information and a print_info() method. The constructor shou

nika2105 [10]

Answer:

class Artist():

def __init__(self, artist_name=None, artist_birth_year=0, artist_death_year=0):

self.artist_name = artist_name

self.artist_birth_year = artist_birth_year

self.artist_death_year = artist_death_year

def display_artist(self):

if self.artist_death_year == -1:

print('{}, born {}'.format(self.artist_name, self.artist_birth_year))

else:

print('{} ({}-{})'.format(self.artist_name, self.artist_birth_year, self.artist_death_year))

class Artwork():

def __init__(self, artwork_title=None, artwork_year_created=0, artist=Artist()):

self.artwork_title = artwork_title

self.artwork_year_created = artwork_year_created

self.artist = artist

def display_artist(self):

print('artwork_title: {}'.format(self.artwork_title))

print('Artist: ', end='')

self.artist.display_artist()

def main():

user_artist_name = input('Enter the name of artist: ')

user_birth_year = int(input('Enter birth year: '))

user_death_year = int(input('Enter death year: '))

user_title = input('Enter master piece title: ')

user_year_created = int(input('Enter year created: '))

user_artist = Artist(user_artist_name, user_birth_year, user_death_year)

new_artwork = Artwork(user_title, user_year_created, user_artist)

new_artwork.display_artist()

if __name__ == "__main__":

main()

Explanation:

Inside the constructor of Artist class, initialize the essential properties.
Create the display_artist function that checks whether artist_death_year is equal to -1 and then displays an appropriate message according to the condition.
Apply the similar steps as above for the Artwork class.
Inside the main method, get the information from user and finally call the display_artist function to print the results on screen.

8 0

3 years ago

The net force on a vehicle that is accelerating at a rate of 1.2 m/s2 is 1500 newtons. What is the mass of the vehicle to the ne

Rudiy27

Answer:

The mass of the vehicle is 1250kg

Explanation:

Given

$Net\ Force = 1500N$

$Acceleration = 1.2m/s^2$

Required

Determine the vehicle's mass

This question will be answered using Newton's second law which implies that:

$Net\ Force (F) = Mass (m) * Acceleration (a)$

In other words:

$F = ma$

Substitute values for F and a

$1500 = m * 1.2$

Make m the subject

$m = \frac{1500}{1.2}$

$m = 1250kg$

Hence, the mass of the vehicle is 1250kg

6 0

3 years ago

Specialized vocabularyis known as:

svet-max [94.6K]

Answer:

"Jargon"

Explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

Specialized vocabulary is sometimes also known as "Jargon" . These are sets of words that are used specifically and uniquely for specific sets of groups or organizations.

For example Lawyers Judges and other law enforcement officials have their own Specialized vocabulary that are better understood by other people in Law enforcement, people that are not part of Law Enforcement might have a hard time understanding.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

4 0

3 years ago