Answer:
Following is given the solution to each part.
All the comments are given above each step so that they can make the logic clear.
I hope it will help you!
Explanation:
It converts the mic input into a string of raw data, then compares it to hundreds, even thousands of voice samples. The output is a polished string of data in words.
Over a TCP connection, suppose host A sends two segments to host B, host B sends an acknowledgement for each segment, the first acknowledgement is lost, but the second acknowledgement arrives before the timer for the first segment expires is True.
True
<u>Explanation:</u>
In network packet loss is considered as connectivity loss. In this scenario host A send two segment to host B and acknowledgement from host B Is awaiting at host A.
Since first acknowledgement is lost it is marked as packet lost. Since in network packet waiting for acknowledgement is keep continues process and waiting or trying to accept acknowledgement for certain period of time, once period limits cross then it is declared as packet loss.
Meanwhile second comes acknowledged is success. For end user assumes second segments comes first before first segment. But any how first segment expires.
Answer:
The size on the drive before the transfer is 45 megabytes
Explanation:
Before transfer, t which is the time in seconds is 0. Therefore given the formula: S = 5t + 45,
substituting t into the formula gives;
S = 5(0) + 45
S = 0 + 45
S = 45
