Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
Answer:false
Step-by-step explanation:no constant rate of change in y and x values
Answer: 10
Step-by-step explanation:
So since this is all about perimeter you just got to add the values together. So lets use 12 as the denominator for every fraction. 1/4 is equal to 3/12 and 2/3 is equal to 8/12. So in conclusion 3/12 plus 8/12 and 1/12 will equal 1 in total. and then add up all the whole numbers 4 + 2 + 3 + 1 will get you 10. So 10 is your answer.
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