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velikii [3]
3 years ago
8

Use place value to find the product of 40 x 8

Mathematics
2 answers:
AnnZ [28]3 years ago
4 0
480 u do 4x8 and add the zero! (Explanation in case the teacher asks u)
vichka [17]3 years ago
4 0
The answer is 320 that is the answer
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F ∠A is 95° and ∠B is 105°, what is ∠C?<br> A) 75° <br> B) 85° <br> C) 95° <br> D) 105°
Jobisdone [24]

The question is missing important data. The quadrilateral having vertices A, B, C and D is a cyclic quadrilateral.

Answer:

B) 85°

Step-by-step explanation:

Given:

A cyclic quadrilateral with ∠A is 95° and ∠B is 105°.

For a cyclic quadrilateral, the sum of the opposite interior angles is equal to 180°

Therefore, sum of angles A and C is 180°.

\angle A + \angle C=180\°\\95\°+\angle C=180\°\\\angle C=180-95\\\angle C =85\°

Therefore, the correct option is option B) 85°

6 0
4 years ago
Read 2 more answers
Find the volume of the solid generated by revolving the region bounded by the lines and curves about the x-axis. y = x, y =1, x
liraira [26]

Answer:

The volume is: V = \frac{\pi}{3} cubic units

Step-by-step explanation:

Volume of a solid:

The volume of a solid, given by the function f(x), over an interval between a and b, is given by:

V = \pi \int_{a}^{b} (f(x))^2 dx

y = x, y =1, x = 0

This means that the upper function is y = 1, and the lower function is y = x. So

f(x) = (1 - x)

The lower limit of integration is x = 0.

The upper limit is y = x when y = 1, so x = 1.

Then

V = \pi \int_{a}^{b} (f(x))^2 dx

V = \pi \int_{0}^{1} (1-x)^2 dx

V = \pi \int_{0}^{1} (1-2x+x^2) dx

V = \pi (x-x^2+\frac{x^3}{3})|_{0}^{1} dx

V = \pi(1 - (1^2) + \frac{1^3}{3})

V = \frac{\pi}{3}

8 0
3 years ago
Subtract 5y ^2−6y−115, y, squared, minus,
Tamiku [17]

Answer:

y^2+8y+16

Step-by-step explanation:

6y^2 +2y +5 - ( 5y^2 -6y-11)

Distribute the minus sign

6y^2 +2y +5 -  5y^2 +6y+11

Combine like terms

y^2+8y+16

5 0
3 years ago
Read 2 more answers
The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulbs. The
Bond [772]

Answer:

34% of lightbulb replacement requests numbering between 47 and 52

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 52

Standard deviation = 5

Between 47 and 52:

52 is the mean and 47 is one standard deviation below the mean.

By the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean.

Since the normal distribution is symmetric, of those, 34% are within 1 standard deviation below the mean and the mean(47 and 52) and 34% are within the mean and one standard deviation above the mean(52 and 57).

So

34% of lightbulb replacement requests numbering between 47 and 52

3 0
3 years ago
On 1 May 2012, the cost of 5 grams of gold was 14 000 rupees.
navik [9.2K]

Answer:

51,800 rupees

Step-by-step explanation:

Cost of 5 grams of gold on 1 May 2012 = 14 000 rupees.

The cost of gold decreased by 7.5% from 1 May 2012 to 1 May 2013

Cost of 5 grams of gold on 1 May 2013 = 14,000 - 7.5% of 14,000

= 14,000 - 0.075 × 14,000

= 14,000 - 1,050

= 12,950 rupees

Work out the cost of 20 grams of gold on 1 May 2013

Since, there are four 5 grams of gold in 20 grams of gold

Therefore,

Cost of 20 grams of gold on 1 May 2013 = 12,950 rupees × 4

= 51,800 rupees

4 0
3 years ago
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