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Pani-rosa [81]
3 years ago
12

Anyone good with Circumference? Please help me :c (10 points)

Mathematics
1 answer:
nlexa [21]3 years ago
8 0

Answer:

c = 49794.24

Step-by-step explanation:

c = 2\pi r = 2.\pi.7925\\c = 49794.24356

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For an angle θ with the point (−5, −12) on its terminating side, what is the value of cosine?
viva [34]

Answer:

option C. -\frac{5}{13}

Step-by-step explanation:

we have  that

The point (-5,-12) belong to the III quadrant

so

The value of the cosine is negative

Applying the Pythagoras Theorem

Find the value of the hypotenuse

h^{2}=5^{2}+12^{2}\\ h^{2} =25+144\\ h^{2}=169\\h=13\ units

The value of cosine of angle θ is the ratio between the side adjacent to angle θ and the hypotenuse

cos(\theta)=-\frac{5}{13}

8 0
3 years ago
What’s the radius of this button ?
Neporo4naja [7]

Answer:

2.5 cm

Step-by-step explanation:

We see the diameter is 5cm

so the radius is half the diameter

5/2 = 2.5 cm

3 0
3 years ago
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Find the midpoint of the segment with the following end points (10,5) and (6,9)
Taya2010 [7]

Answer:

The mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)

Step-by-step explanation:

Let (x, y) be the mid-point

Given the points

  • (10,5)
  • (6,9)

Using the formula to find the mid-point between the endpoints (10,5) and (6,9)

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

Here:

\left(x_1,\:y_1\right)=\left(10,\:5\right),\:\left(x_2,\:y_2\right)=\left(6,\:9\right)

Thus,

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

\left(x,\:y\right)=\left(\frac{6+10}{2},\:\frac{9+5}{2}\right)

\left(x,\:y\right)=\left(8,\:7\right)

Therefore, the mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)
3 0
3 years ago
An explanation for this question would be nice it is okay if not :)
Vsevolod [243]

answer :- x+x² hope you understand

5 0
3 years ago
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Which graph represents an exponential function?
Kobotan [32]

Answer:

The second one

Step-by-step explanation:

If you know about hyper and Para bolas then the second one also know as a frowny fave parabola is a function

3 0
3 years ago
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