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anastassius [24]

3 years ago

10

You stand 25 m from the base of a tree and the angle of elevation from the ground to the top of the tree is 48 degrees. How tall

is the tree?

1 answer:

madam [21]3 years ago

8 0

Answer:

ffyftxrrxrrxcvcmuvcyztzxvujgyh

Step-by-step explanation:

✋☝☝✊✋❤❤❤

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A pair of Jordans sold at retail for $180 and now sell for $330 after market. A. Is this a percent INCREASE or DECREASE, what is

Elza [17]

Answer:

This is a percent INCREASE

The percent change is 83.33%

Step-by-step explanation:

Let us solve the question

∵ A pair of Jordans sold at retail for $180

∴ The initial price = 180

∵ Now it sells for $330 aftermarket

∴ The new price = 330

→ That means the new price is greater than the initial price

∵ The new price is greater than the initial price

∴ This is a percent INCREASE

∵ The percent of change = (amount of increase ÷ initial amount) × 100%

∵ The amount of increase = new price - initial price

∴ The amount of increase = 330 - 180 = 150

→ Substitute it in the rule of percent of increase above

∵ The percent change = $\frac{150}{180}$ × 100%

∴ The percent change = $\frac{5}{6}$ × 100%

∴ The percent change = 83.33%

4 0

3 years ago

Please solve this quickly

adell [148]

Answer:

I Didn't see nothing

Step-by-step explanation:

So I can't help you

7 0

3 years ago

Read 2 more answers

Anna71 [15]

Answer:

h(x)

h(x)

f(x) g(x) h(x)

Step-by-step explanation:

Edge 2020

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6 0

3 years ago

Max correctly solved this inequality.

Dafna11 [192]

Answer:

B

Step-by-step explanation:

Got it right on edge. mark me brainliest please

6 0

3 years ago

The manager of a music store has kept records of

Marysya12 [62]

Answer:

(a) $P(x\le 3) = 0.75$

(b) $P(x\le 3) = 0.75$

<em>(b) is the same as (a)</em>

(c) $P(x \ge 5) = 0.10$

(d) $P(x = 1\ or\ 2) = 0.55$

(e) $P(x > 2) = 0.45$

Step-by-step explanation:

Given

$\begin{array}{ccccccc}{CDs} & {1} & {2} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.30} & {0.25} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}$

Solving (a): Probability of 3 or fewer CDs

Here, we consider:

$\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}$

This probability is calculated as:

$P(x\le 3) = P(1) + P(2) + P(3)$

This gives:

$P(x\le 3) = 0.30 + 0.25 + 0.20$

$P(x\le 3) = 0.75$

Solving (b): Probability of at most 3 CDs

Here, we consider:

$\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}$

This probability is calculated as:

$P(x\le 3) = P(1) + P(2) + P(3)$

This gives:

$P(x\le 3) = 0.30 + 0.25 + 0.20$

$P(x\le 3) = 0.75$

<em>(b) is the same as (a)</em>

<em />

Solving (c): Probability of 5 or more CDs

Here, we consider:

$\begin{array}{ccc}{CDs} & {5} & {6\ or\ more}\ \\ {Prob} & {0.05} & {0.05}\ \ \end{array}$

This probability is calculated as:

$P(x \ge 5) = P(5) + P(6\ or\ more)$

This gives:

$P(x\ge 5) = 0.05 + 0.05$

$P(x \ge 5) = 0.10$

Solving (d): Probability of 1 or 2 CDs

Here, we consider:

$\begin{array}{ccc}{CDs} & {1} & {2} \ \\ {Prob} & {0.30} & {0.25} \ \ \end{array}$

This probability is calculated as:

$P(x = 1\ or\ 2) = P(1) + P(2)$

This gives:

$P(x = 1\ or\ 2) = 0.30 + 0.25$

$P(x = 1\ or\ 2) = 0.55$

Solving (e): Probability of more than 2 CDs

Here, we consider:

$\begin{array}{ccccc}{CDs} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}$

This probability is calculated as:

$P(x > 2) = P(3) + P(4) + P(5) + P(6\ or\ more)$

This gives:

$P(x > 2) = 0.20+ 0.15 + 0.05 + 0.05$

$P(x > 2) = 0.45$

3 0

3 years ago