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anastassius [24]

2 years ago

10

You stand 25 m from the base of a tree and the angle of elevation from the ground to the top of the tree is 48 degrees. How tall

is the tree?

1 answer:

madam [21]2 years ago

8 0

Answer:

ffyftxrrxrrxcvcmuvcyztzxvujgyh

Step-by-step explanation:

✋☝☝✊✋❤❤❤

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The Sine Function

lara [203]

Answer:

A. 93.3

Step-by-step explanation:

I calculated it logically

4 0

2 years ago

JNZ~ KOA. Find the unknown measures

shepuryov [24]

Answer:

<h2>x = 8.5in, y = 17in, r = 28°, s = 62°</h2>

Step-by-step explanation:

If ΔJNZ and ΔKOA are similar, then corresponding sides are in proportion and corresponding angles are congruent.

We have the proportion:

$\dfrac{JN}{KO}=\dfrac{NZ}{OA}=\dfrac{ZJ}{AK}$

and equations:

$m\angle N=m\angle O=90^o\\m\angle Z=m\angle A=28^o\\m\angle J=m\angle K=62^o$

We have:

$JN=8\ in,\ NZ=15\ in,\ KO=4\ in,\ AK=x\ in,\ ZJ=y\ in$

For y we must use the Pythagorean theorem:

$ZJ^2=JN^2+NZ^2\\\\y^2=8^2+15^2\\\\y^2=64+225\\\\y^2=289\to y=\sqrt{289}\\\\y=17\ in$

$\dfrac{JN}{KO}=\dfrac{ZJ}{AK}\to\dfrac{8}{4}=\dfrac{17}{x}$ <em>cross multiply</em>

$8x=(4)(17)$

$8x=68$ <em>divide both sides by 8</em>

$x=8.5\ in$

4 0

2 years ago

Read 2 more answers

If 18-6x is 4 less than -8, what is the value of -3x?

UNO [17]

Answer:

-15

Step-by-step explanation:

x=5

4 0

3 years ago

Read 2 more answers

Rewrite the statement in mathematical notation. (Let y be the distance from the top of the ladder to the floor, x be the distanc

In-s [12.5K]

Answer:

$\frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}$

Step-by-step explanation:

Let L be the length of the ladder,

Given,

x = the distance from the base of the ladder to the wall, and t be time.

y = distance from the base of the ladder to the wall,

So, by the Pythagoras theorem,

$L^2 = y^2 + x^2$

$\implies L = \sqrt{y^2 + x^2}$ ,

Differentiating with respect to time (t),

$\frac{dL}{dt}=\frac{d}{dt}(\sqrt{x^2 + y^2})$

$=\frac{1}{2\sqrt{x^2 + y^2}}\frac{d}{dt}(x^2 + y^2)$

$=\frac{1}{2\sqrt{x^2 + y^2}}(2x\frac{dx}{dt}+2y\frac{dy}{dt})$

$=\frac{1}{\sqrt{x^2 +y^2}}(x\frac{dx}{dt}+y\frac{dy}{dt})$

Here,

$\frac{dy}{dt}=-6\text{ ft per sec}$

Also, $\frac{dL}{dt} = 0$ ( Ladder length = constant ),

$\implies \frac{1}{\sqrt{x^2 +y^2}}(x(-6)+y\frac{dy}{dt})=0$

$-6x + y\frac{dy}{dt}=0$

$y\frac{dy}{dt}=6x$

$\implies \frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}$

Which is the required notation.

8 0

3 years ago

Choose the table that represents g(x) = 3⋅f(x) when f(x) = x − 1.

Nastasia [14]

$\bf f(x)=x-1\qquad \qquad g(x)=3\cdot f(x)\implies g(x)=\underline{3(x-1)} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{ccll} x&g(x)\\ \cline{1-2} 1&0\\2&3\\3&6 \end{array}\qquad \qquad (\stackrel{x_1}{1}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{6})$

$\bf slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-0}{3-1}\implies \cfrac{6}{2}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=3(x-1)\implies y=\underline{3(x-1)}$

7 0

2 years ago

Read 2 more answers