We need the diagram pic, otherwise we cant solve your problem.
Answer:
3 standard deviations
from the mean is 6 pounds to 18 pounds.
Step-by-step explanation:
The above question is solved using empirical rule
99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ
From the above question
μ = 12 pounds
σ = 2 pounds
Hence:.
3 standard deviations from the mean is calculated as
μ - 3σ
[12 - 3(2)] pounds
=( 12 - 6) pounds
= 6 pounds
μ + 3σ
[12 + 3(2)] pounds
=( 12 + 6) pounds
= 18 pounds
Hence,3 standard deviations
from the mean is 6 pounds to 18 pounds.
on:
Answer:
S=32 D=34
Step-by-step explanation:
{-----------------VARIABLES------------}
D=Drake
S=Stephanie
TA=Total Age
{----------------GIVEN/EQUATIONS-------------}
D=S+2
TA=D+2s
{--------------SUB/SOLVE---------------}
98=D+2S
SUB FOR D
98=3S+2
96=3S
S=32
D=S+2
D=34
Answer:
Natalie have left with 5 beads.
Step-by-step explanation:
Given:
Natalie had 64 beads. She used 24 beads to make a bracelet. She used 7/8 of the remaining beads to make a necklace.
Now, to find the beads does Natalie have left.
<em>Total beads Natalie had = 64 beads.</em>
<em>And beads she used to make a bracelet = 24 beads</em>.
So, the remaining beads are = ![64-24=40\ beads.](https://tex.z-dn.net/?f=64-24%3D40%5C%20beads.)
Now,<em> the beads she used to make a necklace</em> = ![40 of \frac{7}{8}](https://tex.z-dn.net/?f=40%20of%20%5Cfrac%7B7%7D%7B8%7D)
= ![40\times \frac{7}{8}](https://tex.z-dn.net/?f=40%5Ctimes%20%5Cfrac%7B7%7D%7B8%7D)
= ![\frac{280}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B280%7D%7B8%7D)
=
Hence, the beads Natalie have left = remaining beads - beads used to make necklace.
![The\ beads\ Natalie\ have\ left\ =\ 40-35](https://tex.z-dn.net/?f=The%5C%20beads%5C%20Natalie%5C%20have%5C%20left%5C%20%3D%5C%2040-35)
![The\ beads\ Natalie\ have\ left\ =\ 5\ beads.](https://tex.z-dn.net/?f=The%5C%20beads%5C%20Natalie%5C%20have%5C%20left%5C%20%3D%5C%205%5C%20beads.)
Therefore, Natalie have left with 5 beads.