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murzikaleks [220]
3 years ago
12

find the equation of a line that goes through the point (2,-3) and is perpendicular to the line y= -2/5x+6

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
8 0
Find the negative reciprocal of the given line's slope in order to determine what the slope of the line will be.

-2/5 -> -5/2 -> 5/2

Your line now looks like this: y = 5/2x + b

Now, substitute the given point into the y and x variables and solve for b.

   y = 5/2x + b
  -3 = 5/2(2) + b
  -3 = 5 + b
  -8 = b

You are now done. The line is y = 5/2x - 8.
erica [24]3 years ago
6 0
To get a perpendicular line to y=-2/5x+6 all you need to do is get the negative reciprocal of the slope then use (2,-3) and point slope formula to get your new equation.

y=-2/5x+6 

m=-2/5   so new equation slope is m=5/2


y−b=m(x−a<span>)   or y-y1=m(x-x1)</span>

point is (2,-3)

plug and chug

y-(-3)=5/2(x-2)
y=5/2x-8


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SUPER URGENT: Complete the general form of the equation of a sinusoidal function having an amplitude of 6, a period of 2pi/3, an
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
Given the function f(x) = 3|x – 2| + 6, for what values of x is f(x) = 18?
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Answer:

x = - 2, x = 6

Step-by-step explanation:

Given f(x) = 18 we require to solve

3 | x - 2 | + 6 = 18 ( subtract 6 from both sides )

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The absolute value function always returns a positive value, however, the expression inside can be positive or negative, thus

x - 2 = 4 ( add 2 to both sides )

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As a check substitute these values into the left side of the equation and if equal to the right side then they are the solutions

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