Givens
Slower plane
r = r
t = 2.5 hours
d = d
Faster Plane
r_faster = 1.5 * r
t = 2.5 hours
d1 = d + 127.5
The time is the same for both
t = d/r
d1/r1 = d/r
(d+ 127.5)/1.5r = d/r Multiply each side by r
(d + 127.5)/1.5 = d Multiply both sides by 1.5
d + 127.5 = 1.5d Subtract d from both sides.
127.5 = 1.5d - d
127.5 = 0.5d Divide by 0.5
127.5 / 0.5 = d
255 = d
Now you can go back and figure out the rates.
First find d1
d1 = d + 127.5
d1 = 255 + 127.5
d1 = 382.5
<em><u>Rate of the slower plane</u></em>
d = 255
t = 2.5 hours
r = d/t
r = 255/2.5
r = 102 miles per hour.
<em><u>Faster plane</u></em>
d1 = 382.5 miles
t = 2.5 hours
r1 = d/t
r1 = 382.5/2.5 = 153 miles per hour.
Answer:
$3806
Step-by-step explanation:
230.0
56.0
+ 19.50
305.50
305.5x12=3666
35x4=140
3666+140=3806
Answer:
7/3x -y = 10
Step-by-step explanation:
do you want an explanation?
plz brainliest :)
Answer:
b) π /16 (1-1/e^2)
Step-by-step explanation:
For this case we have the following limits:
And we have semicircles perpendicular cross sections.
The area of interest is the enclosed on the picture attached.
So we are assuming that the diameter for any cross section on the region of interest have a diameter of
And then we can find the volume of a semicircular cross section with the following formula:
And for th volum we can integrate respect to x and the limits for x are from 0 to 1, so then the volume would be given by this:
And evaluating the integral using the fundamental theorem of calculus we got:
And then the best option would be:
b) π /16 (1-1/e^2)