Difference of 2 perfec squares is
(a^2)-(b^2)
if the exponents are both even and the coeficient (the number in front) are perfect squares, then it is difference t 2 perfect squares
first one
8 is not perfect square
2nd one
(4e^4)^2-(9g^2)^2
third
25 is odd, so it cannot be split up into 2 nice numbers
4th
(11m^9)^2-(3n^5)^2
Answer:
I'm pretty sure the answer is 8.96
Step-by-step explanation:
1.28×7=8.96
Answer:
A'(-4,-3)
Step-by-step explanation:
use formula of reflection over y axis
(x,y)=(-x,y)
A(4,-3)=A'(-4,-3)
Answer:
x = 0
Step-by-step explanation:
6 - 2x = 6x - 10x + 6
1. Isolate the variable (x)
6 - 2x = 6x - 10x + 6 -> 6 = 6x - 10x + 2x + 6
- Subtract 6 from both sides
6x - 10x + 2x + 6 -> 0 = 6x - 10x + 2x
2. Combine like terms
0 = 6x - 10x + 2x -> 0 = -2x
3. Solve
0 = x
*Note: 0 divided by anything is 0 so 0/-2 is 0
(unless it is 0/0 which equals 1)
