Need help pls 18 POINTS IF YOU HELP. On #6 pls.

PLZ HELP!!!!!! WILL GIVE BRAINLIEST!!!!!!! Which of the following numbers are greater than -185/100 ? Choose all answers that ap

lesya [120]

Answer:

All of the above.

Step-by-step explanation:

-185/100 is equal to -1.85.

-1.08 is greater because it is closer to 0 than -1.85.

190/100 is equal to 1.9. That's greater because it's in the positives.

-35/20 is equal to -1.75, which is closer to 0 than -1.85.

Therefore, all of the options are greater.

3 0

4 years ago

Read 2 more answers

Please help What is 45% of 350?

a_sh-v [17]

We will want to multiply .45 ( the decimal form of 45%) by 350
.45 * 350 = 157.5

5 0

3 years ago

Read 2 more answers

Find the area of this figure

QveST [7]

Answer: A = 89 m²

Step-by-step explanation:

A = BH -½bh

A = 13(8) - ½(13-4-4)(6)

A = 89 m²

8 0

3 years ago

The area of a square floor on a scale drawing is 64 square centimeters, and the scale drawing is 1 centimeter:3 ft. What is the

Oxana [17]

Answer:

Part a) The area of the actual floor is $576\ ft^{2}$

Part b) The ratio of the area in the drawing to the actual area is $\frac{1}{9}\frac{cm^{2}}{ft^{2}}$

Step-by-step explanation:

we know that

The scale drawing is $\frac{1}{3}\frac{cm}{ft}$

step 1

Find the dimensions of the square on a scale drawing

The area of a square is equal to

$A=b^{2}$

where

b is the length side of the square

$A=64\ cm^{2}$

so

$64=b^{2}$

$b=8\ cm$

step 2

Find the dimensions of the actual floor

Divide the length of the floor on the drawing by the scale drawing

$8/(1/3)=24\ ft$

step 3

Find the area of the actual floor

The area of a square is equal to

$A=b^{2}$

substitute

$A=24^{2}=576\ ft^{2}$

step 4

Find the ratio of the area in the drawing to the actual area

$\frac{64}{576}\frac{cm^{2}}{ft^{2}}$

Simplify

Divide by 64 both numerator and denominator

$\frac{1}{9}\frac{cm^{2}}{ft^{2}}$

3 0

3 years ago

Show all work to identify the asymptotes and zero of the function f(x) = 6x / x^2 - 36

eduard

Answer:

Zero of the function f(x) is at x = 0

Vertical Asymptotes at x = ±6

Horizontal Asymptotes at y = 0

Step-by-step explanation:

<h3>Vertical Asymptotes </h3>

For a given function f(x):

Vertical Asymptotes are obtained at those values of x, where the function f(x) tends to infinity, I.e.,

When x approaches some constant value but the curve moves towards infinity.

If f(x) is a fraction, it'll tend to infinity when it's denominator becomes zero.

Vertical Asymptotes of the given function can be obtained by walking thru the following steps:

Step I

(Factorise the numerator and denominator)

$\mathsf{ f(x) = \frac{6x}{ {x}^{2} - 36 } }$

x² - 36 can be factorised into (x + 6)(x - 6)

and, ofcourse, we can write 6x as 6(x - 0)

$\mathsf{ f(x) = \frac{6(x - 0)}{ (x + 6)(x - 6) } }$

Step II

(Reduce the fraction to its simplest form by canceling out the common factors)

There aren't any common factors in the numerator and denominator in this case.

Step III

(Look for the values of x which cause the denominator to be zero)

If we put x = 6

denominator becomes 0

Also,

If we substitute x with -6

denominator becomes 0.

The two values of x indicate the two Vertical Asymptotes of the function f(x).

Therefore,

Vertical Asymptotes of the given function f(x) are:

$\boxed{ \mathsf{x = \pm6}}$

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3 /><h3>Horizontal Asymptotes:</h3>

Horizontal Asymptotes are obtained When x tends to infinity and y approaches some constant value.

I'll be using the concept of limits for this.

$\mathsf{y = \frac{6x}{ {x}^{2} - 36 } }$

dividing and multiplying by x² (Yep! so if x becomes infinity 1/ x and 1/ x² all such terms become 0, 'cause 1/ ∞ is 0)

$\implies \mathsf{y = lim_{x \rightarrow \infty }( \frac{ \frac{6x}{ {x}^{2} } }{ \frac{ {x}^{2} - 36 }{ {x}^{2} } } ) }$

$\implies \mathsf{y = lim_{x \rightarrow \infty }( \frac{ \frac{6}{ x } }{ 1- \frac{36 }{ {x}^{2} } } ) }$

Substitute x with ∞, you get zero/ 1

$\implies \boxed{\mathsf{y = 0}}$

So, the horizontal Asymptote of the function is y = 0, that is the x axis

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3>Zeroes of a function:</h3>

The values of x that reduces f(x) to zero are called the zeroes of f(x).

Here, only x = 0 acts as the zero of the function.

[NOTE:

For finding Vertical Asymptotes,Equate the denominator to 0. And
For finding Zeroes, Equate the numerator to 0]

__________________

[That's what it's graph looks like. ]

3 0

3 years ago