The given quadrilateral is a kite.
Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)
Firstly, we find the distance between AD and DC
AD = 
⇒ AD = 
⇒ AD = 5
DC = 
⇒ DC =
⇒ DC = 5
Hence, AD = DC = 5
Now, find the distance between AB and BC
AB = 
⇒ AB = 
⇒ AB = 
⇒ AB = 
BC = 
⇒ BC = 
⇒ BC = 
⇒ BC =
Hence, AB = BC = √97
In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.
Hence, it follows the property of kite.
For more questions on quadrilateral, visit:
brainly.com/question/23935806
#SPJ9
Answer:
5.65%
Step-by-step explanation:
Principal=$600
Time=20 years
FV=600*3=$1800
n=1
r=?
r= n[(A/P)^1/nt - 1]
=1{(1800/600)^ 1/1*20 - 1}
={(3)^1/20-1}
=3^0.05-1
=1.0565-1
=0.0565
rate=0.0565*100
=5.65% to the nearest hundredth percent
Answer:
the most basic case, three-dimensional model can be created from simple shapes like cubes, rectangles, and triangles. These shapes are then modified into complex, high-polygon designs.At the same time, the geometric model provides essential information to the system model, including critical sizing and tolerances, other physical properties, and mechanical interconnection.
Step-by-step explanation:
hope this helps if not let me know have a good rest of your day
Answer:
Step-by-step explanation:
Given that,
Michael is cutting a 100-yard ribbon into pieces 3.4 yards long.
Michael says that an inequality that represents his project is 3.4x 100.
Let Michael cuts the ribbon in x no of variables. It is given as :
3.4x is the total length of all the pieces together
i.e.
3.4x is less than or equal to 100.
The required equation that represents the given scanario is :
Answer:
10 years.
Step-by-step explanation:
Present age of Mr. Tanaka = 35 years
Present age of his son = 5 years
Now let the number of years be x. As after x years both of their age will increased by x years, therefore
After x years age of Mr. Tanaka = 35 + x
After x years age of his son = 5 + x
According to question,
Mr.Tanaka's age after x years = 3 (His son's age after x years)
35 + x = 3 (5 + x)
Further solving,
35 + x = 15 + 3x
3x - x = 35 - 15
2x = 20
x = 10
Therefore after 10 years Mr. Tanaka's age will be exactly three times as old as his son. As after 10 years Mr. tanaka's age will be 45 and his son's age will be 15.
