Question

A bicycle rider sees a car up ahead, and slows down to avoid a collision. He starts off traveling at 15 m s and slows down to 5 m s in 7.5 s. Find the acceleration of the bike rider.

Answer 1

Answer:

$a = -1.33 m/s^2$

Explanation:

As we know that acceleration is rate of change in velocity

So here we have

$a = \frac{v_f - v_i}{t}$

so we will have

$v_f = 5 m/s$

$v_i = 15 m/s$

t = 7.5 s

now we have

$a = \frac{5 - 15}{7.5}$

$a = -1.33 m/s^2$