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3 years ago

Heterogeneous Mixture And Homogeneous Mixture

Physics

1 answer:

sdas [7]3 years ago

7 0

Answer: Go ask your teacher and im sure if you search it on good it will answer faster than this.

Explanation: Have a great day \ and be safe

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Una araña con una masa de 0.26g cuelga verticalmente de uno de sus hilos. El hilo tiene una constante de resorte de 7.1N/m. ¿Cuá

pochemuha

Answer:

Extension, e = 0.0000359 meters

Explanation:

Given the following data;

Mass = 0.26 g

Spring constant = 7.1 N/m

To find the extension of the thread;

Conversion:

1000 grams = 1 kg

0.26 grams = 0.26/1000 = 0.00026 kg

First of all, we would determine the force acting on the spider;

Force = mass * acceleration due to gravity

Force = 0.00026 * 9.8

Force = 0.00255 N

Next, we would determine the extension;

Force = spring constant * extension

Substituting into the equation, we have

0.00255 = 7.1 * extension

Extension, e = 0.00255/7.1

Extension, e = 0.0000359 meters

7 0

3 years ago

3.Cuanto Calor pierden 514 ml de agua si su temperatura desciende de 12°C a 11°C. Expresa el resultado en calorias.

Scrat [10]

Answer:

514 cal

Explanation:

In order to calculate the lost heat by the amount of water you first take into account the following formula:

$Q=mc(T_2-T_1)$ (1)

Q: heat lost by the amount of water = ?

m: mass of the water

c: specific heat of water = 1cal/g°C

T2: final temperature of water = 11°C

T1: initial temperature = 12°C

The amount of water is calculated by using the information about the density of water (1g/ml):

$m=\rho V=(1g/ml)(514ml)=514g$

Then, you replace the values of all parameters in the equation (1):

$Q=(514g)(1cal/g\°C)(11\°C-12\°C)=-514cal$

The amount of water losses a heat of 514 cal

3 0

4 years ago

Which situation is an an example of competition that could be found in the grassland

astraxan [27]

A good answer is a giraffe and a tree

4 0

3 years ago

Read 2 more answers

A 56 kg astronaut stands on a bathroom scale inside a rotating circular space station. The radius of the space station is 250 m.

Zielflug [23.3K]

Answer:

The speed of space station floor is 49.49 m/s.

Explanation:

Given that,

Mass of astronaut = 56 kg

Radius = 250 m

We need to calculate the speed of space station floor

Using centripetal force and newton's second law

$F=mg$

$\dfrac{mv^2}{r}=mg$

$\dfrac{v^2}{r}=g$

$v=\sqrt{rg}$

Where, v = speed of space station floor

r = radius

g = acceleration due to gravity

Put the value into the formula

$v=\sqrt{250\times9.8}$

$v=49.49\ m/s$

Hence, The speed of space station floor is 49.49 m/s.

6 0

3 years ago

If a grocery cart with a mass of 16.5 kg accelerates at +2.31 m/s2 against a frictional force of -15.0 N, what is the applied fo

ziro4ka [17]

Call the applied force 'A'. (Clever ?)

The forces on the cart are 'A' forward and 15 N backward.

The net force on the art is (A-15) forward.

F = m a

Net forward force = (mass of the cart) x (its forward acceleration)

(A - 15) = (16.5) x (2.31)

A - 15 = 38.115

Add 15 to each side:

<u>A = 53.115 newtons</u>

5 0

3 years ago

Read 2 more answers