Answer:
Explanation:
Given:
mass,
time,
velocity,
coefficient of kinetic friction between wheels & pavement,
According to first condition,
According to second condition,
<u>Magnitude of frictional force (which acts opposite to the direction of motion):</u>
where N is the normal reaction.
Now, the impulsive force on the wall if the brakes were applied during the crash:
Answer:
K = 1.29eV
Explanation:
In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:
(1)
Δx : uncertainty of position = 2.0pm = 2.0*10^-12m
Δp: uncertainty of momentum = ?
h: Planck's constant = 6.626*10^-34 J.s
You calculate the minimum possible value of Δp from the equation (1):
The minimum kinetic energy is calculated by using the following formula:
(2)
m: mass of the proton = 1.67*10^{-27}kg
in eV you have:
The kinetic energy of the proton is 1.29eV